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sleet_krkn [62]
3 years ago
6

18 of 25

Physics
2 answers:
anyanavicka [17]3 years ago
7 0

Answer:

B

Explanation:

Cause its true

Nikitich [7]3 years ago
7 0
The answer is B.
Explanation: All science questions/experiments are proven with evidence and many trials
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a wave is described by where x is in meters, y is in centimeters and t is in seconds. The angular frequency is
Sergeeva-Olga [200]

Complete Question

A wave is described by y(x,t) = 0.1 sin(3x + 10t), where x is in meters, y is in centimetres and t is in seconds. The angular wave  frequency is

Answer:

The  value is w =  10 \ rad /s

Explanation:

From the question we are told that  

    The equation describing the wave is y(x,t) = 0.1 sin(3x + 10t)

Generally the sinusoidal equation representing the motion of a wave is mathematically represented as

         y(x,t) =  Asin(kx + wt )

Where  w  is the  angular frequency

Now comparing this equation  with that given we see that

       w =  10 \ rad /s

 

               

7 0
3 years ago
A. Does this graph represent an endothermic or an exothermic reaction? Explain your answer.
ra1l [238]

Answer:

Exothermic reaction

Explanation:

Exothermic reaction relases energy while endothermic absorbs energy.

8 0
3 years ago
You are a project manager for a manufacturing company. One of the machine parts on the assembly line is a thin, uniform rod that
ra1l [238]

Answer:

a) I=0.012\ kg.m^2

b) I=0.012\ kg.m^2

Explanation:

Given that:

  • mass of rod, m=0.4\ kg
  • length of the rod, l=0.6\ kg

<u>(a)</u>

<u>Moment of inertia of rod about its center and perpendicular to the rod is given as:</u>

I=\frac{1}{12} m.l^2

I=\frac{1}{12} 0.4\times 0.6^2

I=0.012\ kg.m^2

(b)

<u>Moment of inertia on bending the rod to V-shape of 60 degree angle and axis being perpendicular to the plane of V at the vertex.</u>

<em>We treat it as two rod with axis of rotation at the end and perpendicular to the plane of rotation. </em>

<em>So, the mass and the length of the rod will become half of initial value.</em>

I=I_1+I_2

I=\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2 +\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2

I=2[ \frac{1}{3}\times 0.2\times 0.3^2]

I=0.012\ kg.m^2

7 0
3 years ago
The name of the bright star near the center that the other stars appear to be circling is:
monitta

Answer:

the sun or Me not sure but one of them has to be ...

3 0
3 years ago
A horizontal pipe narrows from a radius of 0.250 m to 0.1000 m. If the speed of the water in the pipe is 1.00 m/s in the larger-
umka21 [38]

Answer:

6.25 m/s

196 kg/s

Explanation:

The areas of the pipe from big to small:

A = \pi R^2 = \pi*0.25^2 = 0.196 m^2

a = \pi r^2 = \pi*0.1^2=0.0314m^2

As the product of speed and cross-section area is constant, the speed in the smaller pipe would be

AV = av

v = \frac{AV}{a} = \frac{0.196 * 1}{0.0314} = 6.25 m/s

The mass flow rate would be:

\dot{m} = \ro AV = 1000 * 0.196 * 1 = 196 kg/s

4 0
3 years ago
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