Answer is B
Hope this helped!
D. velocity
Velocity depends on speed and direction
Yes, scientific method can be applied on many everyday activities to get a reasonable solution. Infact normally we are applying this method without having it in our knowledge that we are applying it.
For example: In morning we are going to office and we start the car, but it is not started.You turn the engine again and again but it simply donot works.
Observation (the state of defining a problem):
The car is not started
Hypothesis (A possible solution based on the information we already know):
The car is not started because it might be out of gas or there can be some other technical fault.
Experiment (testing of hypothesis by applying different methods of solving problem):
You get the fuel and put it inside the car but it still donot works and car didnot start. Experiment didnot get solution.
Analyze the results of data and test another hypothesis
You call a technician and he check with the car engine tries and finds out that the engine was out of order and needs repairing.
Draw conclusion:
The engine do not works when it is out of order and it is a cause of a car not being started.
<em>Now the theory and law making part can not be applied on this case but it is a part of scientific method.</em>
Hope it helps!
Answer:
<em>The </em><em>heat </em><em>capacity</em><em> </em><em>of </em><em>a </em><em>body </em><em>is </em><em>defined</em><em> </em><em>as </em><em>the </em><em>heat </em><em>required</em><em> </em><em>to </em><em>raise </em><em>it's </em><em>temperature</em><em> </em><em>by </em><em>me </em><em>degree </em><em>or </em><em>one </em><em>kelvin.</em><em>w</em><em>h</em><em>i</em><em>l</em><em>e</em><em> </em><em>specific</em><em> </em><em>heat </em><em>capacity </em><em>of </em><em>a </em><em>substance</em><em> </em><em>is </em><em>defined</em><em> </em><em>as </em><em>the </em><em>heat </em><em>required</em><em> to</em><em> </em><em>the </em><em>temperature</em><em> </em><em>of </em><em>a </em><em>unit </em><em>mass </em><em>of </em><em>it </em><em>through </em><em>one </em><em>degree </em><em>or </em><em>one </em><em>kelvin</em><em>.</em>
<em>I </em><em>hope </em><em>it </em><em>helps</em>
I'll assume you are looking for the mass of the object, since that is the missing piece of the puzzle.
The important equation for heat and energy is
Energy = mass × specific heat × change in temperature
Things we know:
Energy needed is 350 J.
Specific heat = 1.2 J/g°C
Temp. change = (30-20)°
Now we just need to plug those in and rearrange the formula to find the mass!
350 = mass × 1.2 × 10
