Answer:
If the line is curved, the slope is changing, which also means the velocity is changing. In a distance-time graph, the gradient of the line is equal to the speed of the object. The more the gradient (and the steeper the line) the faster the object is moving.
The time that the car take to catch up to truck would be :
1/2 ar^2 = vt
1/2 (3) t^2 = 15t
1.5 t^2 = 15t
t ^2 = 10s
Hope this helps
Answer:
Explanation:
5 C = 278 K
25 C = 298 K
V1 / T1 = V2 / T2
1.5L / 278 K = V2 / 298 K
V2 = (1.5L * 298) / 278
V2 = 1.61 L
It's velocity when it strikes the ground is. D. 232.9 kg.m/s<span>.
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I hope this helps!!!