Answer:
19.5 m
Explanation:
EN LANZAMIENTO DE PROYECTILES, LA VELOCIDAD HORIZONTAL
PERMANECE CONSTANTE.
PRIMERO ENCUENTRA LA VELOCIDAD VERTICAL
y = 2(
)(1.8 m) =
= 5.94 m/s
LUEGO ENCUENTRAS EL TIEMPO QUE LA FLECHA PERMANECE EN EL
AIRE.
t = 5.94 m/s / = 0.61 s
FINALMENTE ENCUENTRAS LA DISTANCIA HORIZONTAL TOTAL.
x = 32 m/s(0.61 s) = 19.5 m
Answer:
Maximum height will be
Explanation:
We have given initial velocity through which basketball is thrown
Acceleration due to gravity
At maximum height velocity will be zero
So final velocity v = 0 m /sec
According to third equation of motion
( Negative sign is due to upward acceleration )
Answer:
The answer to the question is as follows
The acceleration due to gravity for low for orbit is 9.231 m/s²
Explanation:
The gravitational force is given as
Where = Gravitational force
G = Gravitational constant = 6.67×10⁻¹¹
m₁ = mEarth = mass of Earth = 6×10²⁴ kg
m₂ = The other mass which is acted upon by and = 1 kg
rEarth = The distance between the two masses = 6.40 x 10⁶ m
therefore at a height of 400 km above the erth we have
r = 400 + rEarth = 400 + 6.40 x 10⁶ m = 6.80 x 10⁶ m
and =
= 9.231 N
Therefore the acceleration due to gravity = /mass
9.231/1 or 9.231 m/s²
Therefore the acceleration due to gravity at 400 kn above the Earth's surface is 9.231 m/s²