Answer:
19.5 m
Explanation:
EN LANZAMIENTO DE PROYECTILES, LA VELOCIDAD HORIZONTAL
PERMANECE CONSTANTE.
PRIMERO ENCUENTRA LA VELOCIDAD VERTICAL
y = 2(
)(1.8 m) =
= 5.94 m/s
LUEGO ENCUENTRAS EL TIEMPO QUE LA FLECHA PERMANECE EN EL
AIRE.
t = 5.94 m/s / = 0.61 s
FINALMENTE ENCUENTRAS LA DISTANCIA HORIZONTAL TOTAL.
x = 32 m/s(0.61 s) = 19.5 m
Answer and Explanation:
Data provided in the question
Carbon mass = m
Initial speed = v_i
Coefficient = μk
Based on the above information, the expressions are as follows
a. By using the energy considerations the expression for the carton moving distance is
As we know that
where,
b. The initial speed of the carton if the factor of 3 risen, so the expression is
Assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
Missing part of the question: determine the magnitude of Porsha's acceleration.
Given the data in the question;
Magnitude of Porsha's acceleration;
To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:
Where m is the mass of the object and a is the acceleration.
We substitute the mass of Porsha and the force he used into the equation
Therefore, assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
Learn more: brainly.com/question/25125444