Answer:
60 w
Explanation:
Given :
V= 120V
I=0.5 A
Now,
power can be calculated as :
P=VI
where,
V is voltage
I is current
Now,
P=(120)(0.5)
P=60 W
Therefore, 60w power is delivered to a light
Answer:
The maximum current which can flow through a fuse without melting it, is called its rating. ... If current higher than 8 A flows through the fuse, it would melt and circuit gets broken. ... Hence, fuse acts as a safety device
Answer:
Explanation:
18 km/hr(1000 m/km) / (3600 s/hr) = 5 m/s
36 km/hr = 10 m/s
v² = u² + 2as
a = (v² - u²)/2s
a = (10² - 5²)/2(1000) = 0.0375 m/s²
v² = 10² + 2(0.0375)(1000)
v² = 175
v = 13.22875... ≈ 13 m/s ≈ 48 km/hr
v = u + at
t = (v - u) / a
t = (10 - 5)/0.0375 = 133.333... 133 s
t = (13.22875 - 10) / 0.0375 = 86.1 s
The answer is D. Isotopes.
Hope that helped.
