Answer: 
Step-by-step explanation:
Given the quadratic equation 
, you need to factor it.
In order to find the form asked of the given equation, you need to factor out the common factor of the terms.
You can observe that the common factor of the terms of the equation is: 
Now, knowing this, you must factor out . Then you get the following form:
Therefore, the factored fom of the equation is:
Step-by-step explanation:
the midpoint between 2 points (x1, y1) and (x2, y2) is simply ((x1+x2)/2, (y1+y2)/2).
so,
1.
(9, 7) to (4, -3)
midpoint is ((9+4)/2, (7+ -3)/2) = (13/2, 4/2) = (6.5, 2)
2.
(-7, -5) to (2, 1)
midpoint is ((-7+2)/2, (-5+1)/2) = (-5/2, -4/2) = (-2.5, -2)
3.
now we have the midpoint and need the second point.
(4, 2) over (3, 4) to (x, y)
3 = (4 + x)/2
6 = 4 + x
x = 2
4 = (2 + y)/2
8 = 2 + y
y = 6
4.
(-2, 1) over (-3, 2) to (x, y)
-3 = (-2 + x)/2
-6 = -2 + x
x = -4
2 = (1 + y)/2
4 = 1 + y
y = 3
Answer:
Step-by-step explanation:
domain X is real number
range Y larger or equal to -3 (cause 4x^2 is always >= 0)
Answer:
First, we bring the equation to the form ax²+bx+c=0, where a, b, and c are coefficients. Then, we plug these coefficients in the formula: (-b±√(b²-4ac))/(2a) . See examples of using the formula to solve a variety of equations.
