All categories

3 years ago

H2SO4 is a strong acid, but HSO4- is a weak acid

Chemistry

2 answers:

djyliett [7]3 years ago

6 0

Answer:

Hey here is your ans

Explanation:

H2SO4 is a strong acid. ... HSO4- is the conjugate base of H2SO4 but it can still give its Hydrogen away, and thus it is a weak acid as well. It's weak because it doesn't part with its hydrogen as easily as H2SO4 did

WINSTONCH [101]3 years ago

5 0

Because in H2S04 , Hydrogen has 2 molecules and in HS04, I has one molecule.

You might be interested in

If we use 18 moles of H2 how many moles of H2O do we make? Use this chemical equation: 6H2 + O2 → 3H2O

Ilya [14]

<h3>Answer:</h3>

9 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis
Analyzing reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 6H₂ + O₂ → 3H₂O

[Given] 18 mol H₂

[Solve] mol H₂O

<u>Step 2: Identify Conversions</u>

[RxN] 6 mol H₂ → 3 mol H₂O

<u>Step 3: Stoich</u>

[DA] Set up conversion: $\displaystyle 18 \ mol \ H_2(\frac{3 \ mol \ H_2O}{6 \ mol \ H_2})$
[DA] Simplify: $\displaystyle 18 \ mol \ H_2(\frac{1 \ mol \ H_2O}{2 \ mol \ H_2})$
[DA] Divide [Cancel out units]: $\displaystyle 9 \ mol \ H_2O$

3 0

3 years ago

Read 2 more answers

Does the amount of methanol increase, decrease, or remain the same when an equilibrium mixture of reactants and products is subj

denis23 [38]

Answer:

a. Methanol remains the same

b. Methanol decreases

c. Methanol increases

d. Methanol remains the same

e. Methanol increases

Explanation:

Methanol is produced by the reaction of carbon monoxide and hydrogen in the presence of a catalyst as follows; 2H2+CO→CH3OH.

a) The presence or absence of a catalyst makes no difference on the equilibrium position of the system hence the methanol remains constant.

b) The amount of methanol decreases because the equilibrium position shifts towards the left and more reactants are formed since the reaction is exothermic.

c) If the volume is decreased, there will be more methanol in the system because the equilibrium position will shift towards the right hand side.

d) Addition of helium gas has no effect on the equilibrium position since it does not participate in the reaction system.

e) if more CO is added the amount of methanol increases since the equilibrium position will shift towards the right hand side.

3 0

3 years ago

I need help with these quickkk WILL GIVE BRAINLIEST PLS

DerKrebs [107]

Answer: number 2

Explanation:

8 0

2 years ago

An object that sticks to iron

Dvinal [7]

Answer:

A magnet

Explanation:

4 0

2 years ago

The graph represents the heating of water in a pot. At 150 seconds, the water has just reached a boil. If the heat is left on, w

navik [9.2K]

Temperature will raise and water will evaporate

5 0

2 years ago