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Vitek1552 [10]
3 years ago
8

H2SO4 is a strong acid, but HSO4- is a weak acid

Chemistry
2 answers:
djyliett [7]3 years ago
6 0

Answer:

Hey here is your ans

Explanation:

H2SO4 is a strong acid. ... HSO4- is the conjugate base of H2SO4 but it can still give its Hydrogen away, and thus it is a weak acid as well. It's weak because it doesn't part with its hydrogen as easily as H2SO4 did

WINSTONCH [101]3 years ago
5 0
Because in H2S04 , Hydrogen has 2 molecules and in HS04, I has one molecule.
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professor190 [17]

Answer:

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5 0
3 years ago
In the citric acid cycle, ATP molecules are produced by _____. In the citric acid cycle, ATP molecules are produced by _____. su
monitta

Answer:

substrate-level phosphorylation

Explanation:

Substrate-level phosphorylation is the metabolic reaction which results in formation of energy currency molecules, ATP or GTP by direct transfer of a phosphoryl group to the ADP or GDP from the another phosphorylated compound.

<u>In citric acid cycle, Succinyl-CoA in the presence of succinyl-CoA synthase is converted to succinate. Condensation reaction (Substrate-level phosphorylation) of GDP and Pi takes place which results in the formation of GTP.</u>

3 0
3 years ago
A client has experienced excessive losses of bicarbonate and has subsequently developed an acid–base imbalance. How will this lo
IRISSAK [1]

The kidneys will excrete increased quantities of acid.

Explanation:

The kidneys will excrete excess H+ ions in the blood (remember H+ ions are responsible for acidity) until the acid-base balance is restored in the blood. Bicarbonates, on the other hand, will be aggressively  reabsorbed by the renal tubules as the excess H+ are being excreted.

The acid base balance is mainly determined by the quantities of H⁺ and HCO₃⁻ ions in teh blood. These ions come from the dissociation of carbonic acid formed when carbon dioxide from tissues is dissolved in blood plasma.

6 0
3 years ago
Given the following partial (valence-level) electron configurations,<br> (a) identify each element,
Kamila [148]

The arrangement of electrons within an atom is called the electronic configuration and the electrons are filled up according to the energy of the levels as: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f.

<h3>What is the difference between electron configuration and valence electron configuration?</h3>

Electron configuration is the number of electrons that are present in the atom and is repressed through the different sub-shells. So for example, the electron configuration for oxygen is 1s^2 2s^2 2p^4. While the valence electrons only refer to the electrons in the outermost shell of the atom.

<h3>What is a partial orbital diagram?</h3>

A partial orbital diagram shows only the highest energy sublevels being filled. Al (Z = 13) 1s22s22p63s23p1. A condensed electron configuration has the element symbol of the previous noble gas in square brackets. Al has the condensed configuration [Ne]3s23p1.

Learn more about electronic configuration here:

<h3>brainly.com/question/26084288</h3><h3 /><h3>#SPJ4</h3>

4 0
2 years ago
Do free electrons appear anywhere in the balanced equation for a redox reaction?
Andru [333]

Yes, free electrons appear in balanced redox reaction equations. However, this is only true for half-reactions. This is because redox reactions primarily involve the transfer of electrons, which are better visualized if explicitly shown in the balanced reactions. In reduction reactions, electrons are placed on the left side of the equation. Oxidation reactions show electrons on the right side of the equation.


Explanation:

A half reaction is either the chemical reaction or reduction reaction part of an oxidoreduction reaction. A half reaction is obtained by considering the amendment in chemical reaction states of individual substances concerned within the oxidoreduction reaction. Half-reactions are usually used as a way of leveling oxidoreduction reactions.The half-reaction on the anode, wherever chemical reaction happens, is Zn(s) = Zn2+ (aq) + (2e-).

The metal loses 2 electrons to create Zn2+. The half-reaction on the cathode wherever reduction happens is Cu2+ (aq) + 2e- = Cu(s).

Here, the copper ions gain electrons and become solid copper.

4 0
3 years ago
Read 2 more answers
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