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3 years ago

H2SO4 is a strong acid, but HSO4- is a weak acid

Chemistry

2 answers:

djyliett [7]3 years ago

6 0

Answer:

Hey here is your ans

Explanation:

H2SO4 is a strong acid. ... HSO4- is the conjugate base of H2SO4 but it can still give its Hydrogen away, and thus it is a weak acid as well. It's weak because it doesn't part with its hydrogen as easily as H2SO4 did

WINSTONCH [101]3 years ago

5 0

Because in H2S04 , Hydrogen has 2 molecules and in HS04, I has one molecule.

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If the azeotropic mixture is 72% perchloric acid by mass, what is the mole percent of water in the azeotrope?

WARRIOR [948]

Answer:

Mole percent of water in azeotrope is 69%

Explanation:

Clearly, the azeotrope consists of water and perchloric acid.

So, 72% perchloric acid by mass means 100 g of azeotrope contains 72 g of perchloric acid and 28 g of water.

Molar mass of water = 18.02 g/mol and molar mass of perchloric acid = 100.46 g/mol

So, 72 g of perchloric acid = $\frac{72}{100.46}mol$ of perchloric acid = 0.72 mol of perchloric acid

Also, 28 g of water = $\frac{28}{18.02}mol$ of water = 1.6 mol of water

Hence total number of mol in azeotrope = (1.6+0.72) mol = 2.32 mol of azeotrope

So, mole percent of water in azeotrope = [(moles of water)/(total no of moles)] $\times 100$ %

Mole percent of water = $\frac{1.6}{2.32}\times 100$ % = 69%

3 0

4 years ago

Arrange the following in order of increasing melting point: NaCl, H2O, CH4, C6H4(OH)2.

aliina [53]

Explanation:

one thing to know is that higher surface area = higher boiling point.

NaCl has the smallest surface area, so it's the first one.

H2O has less surface area than methane, so it's second.

Methane has more surface area than H20, so it's third.

The big molecule has the most surface area, so it's last

7 0

3 years ago

A group of scientists are studying observable matter in a cluster of galaxies. They conclude that the cluster has only a small p

lidiya [134]

Answer:

it is because of Dark Matter

Dark Matter, component of the universe whose presence is discerned from its gravitational attraction rather than its luminosity. Dark matter makes up 30.1 percent of the matter-energy composition of the universe; the rest is dark energy (69.4 percent) and “ordinary” visible matter (0.5 percent).

Dark matter is composed of particles that do not absorb, reflect, or emit light, so they cannot be detected by observing electromagnetic radiation. Dark matter is material that cannot be seen directly.

Explanation:

Hope It helps

Have A Nice Day : )

5 0

2 years ago

What amount of a nonelectrolytic solute should be dissolved in 28.9 moles of benzene (C₆H₆) at 25°C to change the vapor pressure

RideAnS [48]

Answer:

The amount of a nonelectrolytic solute that has to be dissolved in 28.9 moles to change the vapor pressure of benzene by 17.9 is 6.31 moles.

Explanation:

Let's see how to solve this, step by step applying Raoult's Law (Colligative property).

Pressure solution = χsolvent . Pressure solvent

You have to consider that Pressure in solution is, Pressure Pure - Pressure in Solution (Solute+Solvent). The statement says, that pressure has fallen 17.9%, so let's find out that

100% ....... 94.2 Torr

17.9 % ...... x

16.86 Torr (after the Rule of 3) - This is the value of decline.

So, 94.2Torr - 16.86 Torr = 77.34 Torr

Now the formula

77.34 Torr = 94.2 Torr . X (where x is molar fraction)

x = moles of benzene / moles of benzene + moles of nonelectrolytic solute

77.34 Torr / 94.2 Torr = X

0.821 = moles of benzene / moles of benzene + moles of nonelectrolytic solute

0.821 = 28.9 moles / 28.9 moles + nonelectrolytic

0.821 (28.9 moles + nonelectrolytic) = 28.9 moles

23.72 moles + 0.821 nonelectrolytic = 28.9 moles

0.821 nonelectrolytic = 28.9 moles - 23.72 moles

0.821 nonelectrolytic = 5.18 moles

nonelectrolytic moles = 5.18 / 0.821

nonelectrolytic moles = 6.31

8 0

3 years ago

What makes a bivalve a bivalve

Brums [2.3K]

Answer:

Bivalve, (class Bivalvia), any of more than 15,000 species of clams, oysters, mussels, scallops, and other members of the phylum Mollusca characterized by a shell that is divided from front to back into left and right valves. ...

Explanation:

hope it helps.^^

#carryonlearning

3 0

3 years ago