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Helga [31]
3 years ago
11

Cindy made tea. She started with 300 grams of water at 20 degrees Celsius. She transferred 18,000 calories to the water. What wa

s the final temperature of the water?
Chemistry
1 answer:
Serjik [45]3 years ago
8 0

Answer:

T final = 80°C

Explanation:

  • Q = mCpΔT

∴ Q = 18000 cal

∴ m H2O = 300 g

∴ Cp H2O (15°C) = 0.99795 cal/g.K ≅ 1 cal/g.K

∴ T1 = 20°C = 293 K

∴ T2 = ?

⇒ 18000 cal = (300 g)(1 cal/g.K)(T2 - 293 K)

⇒ (18000 cal)/(300 cal/K) = T2 - 293 K

⇒ T2 = 293 K + 60 K

⇒ T2 = 353 K (80°C)

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Using the balanced equation for the next few questions: 4 Fe(s) + 30 (9) - 2Fe2O3(s)
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0.075 moles of iron oxide would be produced by complete reaction of 0.15  moles of iron.

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<u><em>0.075 moles of iron oxide would be produced by complete reaction of 0.15  moles of iron.</em></u>

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