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Aliun [14]
3 years ago
15

What is the answer to this definition ?

Physics
1 answer:
Paul [167]3 years ago
6 0

Newton's 2nd law of motion is:    <em>Force</em> = (mass) x (acceleration) .

Force is the only way to change an object's velocity.


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4 years ago
The release of energy by particles of matter that have absorbed extra energy is called what ?
natali 33 [55]
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3 years ago
A single mass m1 = 4.1 kg hangs from a spring in a motionless elevator. The spring is extended x = 13 cm from its unstretched le
wlad13 [49]
We know that by Hooke's Law,
F = kx; where F is the net force on the spring, k is the spring constant and x is the extension.
We are told that all the springs have the same spring constant as the first, so we first calculate its spring constant.
F = ma = 4.1 × 9.81
= 40.2 Newtons
k = 40.2 ÷ 0.13
k = 309 Newtons / m
Now, for the spring under consideration, the mass is
m2 = 12.3 kg
The net force will be the difference of the downward force of the mass's weight and the upward force of the elevator. Thus,
F = 12.3 × 9.81 - 12.3 × 4.2
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7 0
3 years ago
A merter stick pivoted at its center has a 150gm mass suspended at its 20cm mark. a) Where should an 100gm mass be placed to pro
IgorLugansk [536]

Answer:1) 100 gm mass should be placed at 95 cm mark.

2) Mass of 112.5 gm should be placed at 90 cm mark.

Explanation:

For equilibrium of the meter stick the sum of the moment's generated by the masses should be equal and opposite

Answer to part b)

Since a meter stick is 100 cm long and it is pivoted at it's center i.e at 50 cm

Thus

1) Moment generated by 100 gm mass about center = M_{1}=m_{1}g\times r_{1}\\\\M_{1}=0.15\times 9.81\times 0.3=0.44145Nm

Let a mass 'm' be placed at 90 cm mark thus moment it generates equals

M_{2}=m\times 9.81\times 0.4=3.924m

Equating both the moments we get

0.44145=3.924m\\\\\therefore m=\frac{0.44145}{3.924}\times 1000grams\\\\\therefore m= 112.5grams

Answer to part a)

Let the 100 grams weight be placed at a distance 'x' right of center

Moment generated by 100 grams weight equals

M_{1}=0.1\times 9.81\times x

equating the moments of the forces we get

0.1\times 9.81\times x=0.15\times 0.3\times 9.81

\therefore x=\frac{0.4415}{.981}=45centimeters

thus the mass of 100 gm should be placed at 95 cm mark in the scale.

8 0
4 years ago
The ability of a material to bend without breaking
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Im pretty sure the answer if elasticity
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