What letter or pair of letters that represent the element.

What happen when a piece of silver metal is added to the copper sulphate solution

natta225 [31]

Answer:

Explanation:When silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

7 0

2 years ago

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Which compound in each pair is more soluble in water?(b) Calcium phosphate or magnesium phosphate

Sidana [21]

larger is the value of $Ksp$ the higher will the solubility of solid in water.

What is called compound?

In chemistry, a compound is a substance made up of two or more different chemical elements combined in a fixed ratio.
When the elements come together, they react with each other and form chemical bonds that are difficult to break.
These bonds form as a result of sharing or exchanging electrons between atoms.

The equation for the dissociation of a solid MX in water is given below

MX(s) ⇄ Mⁿ⁺(aq) + Xⁿ⁻ (aq)

Assume s be the solubility of MX in pure water, then the equilibrium concentrations of ions are

[ Mⁿ⁺] = s

[ Xⁿ⁻ ] = s

The expression for the solubility product constant ( $Ksp$ ) is as follows

$Ksp$ = [ Mⁿ⁺] [ Xⁿ⁻ ]

= s²

That is, larger is the value of $Ksp$ the higher will the solubility of solid in water.

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6 0

1 year ago

Find the quantinum numbers n,m,l,s for the last of potassium layer pleasee help explain correctly all

Fantom [35]

Answer:

Quantum numbers of the outermost electron in potassium:

$n = 4$ .
$l = 1$ .
$m_l = 0$ .
Either $m_s = 1/2$ .

Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the $4s$ orbital (fourth $s$ orbital.)

The quantum number $n$ (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, $n = 4$ for this electron.

The quantum number $l$ (the angular momentum quantum number) specifies the shape ( $s$ , $p$ , $d$ , etc.) of an electron. $l = 1$ for $s\!$ orbitals (such as the one that contains this electron.

Quantum numbers $n$ and $l$ specify the shape of an orbital. On the other hand, the magnetic quantum number $m_l$ specifies the orientation of these orbitals in space.

However, $s$ orbitals are spherical. Regardless of the value of $n$ , the only possible $m_l$ value for electrons in $s\!$ orbitals is $m_l = 0$ .

The spin quantum number $m_s$ distinguishes between the two electrons in an orbital. The two possible values of $m_s \!$ are $(+1/2)$ and $(-1/2)$ . Typically, the first electron in an orbital is assigned an upward ( $\uparrow$ ) spin, which corresponds to $m_s = (+1/2)$ .