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Alchen [17]
3 years ago
12

I need answer as quick

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Given

(x + 7)(x + 1)(x + 4) ← expand the second/ third factors using FOIL

= (x + 7)(x² + 5x + 4)

= x(x² + 5x + 4) + 7(x² + 5x + 4) ← distribute both parenthesis

= x³ + 5x² + 4x + 7x² + 35x + 28 ← collect like terms

= x³ + 12x² + 39x + 28 → C

Novosadov [1.4K]3 years ago
3 0

Answer:

C

Step-by-step explanation:

(x+7)(x+1)(x+4)=

x^3+12x^2+39x+28 or C

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valentinak56 [21]
The answer is 33 because 40*0.825 or 40*82.5% is 33 men.
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4 years ago
30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 &lt;0
Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}

2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)

\mathrm{Simplify}

-2logx^3-3

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}

-2logx^3-3+3

\mathrm{Simplify}

-2logx^3

Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)

\mathrm{Simplify}

2lx^3og>2\log ^3\left(x\right)-3

\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0

\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\

\mathrm{Simplify}

g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0

Step-by-step explanation:

6 0
3 years ago
5.
nikitadnepr [17]

Answer:

i am not so sure but I think its 10x = 33

3 0
3 years ago
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Answer:

0.73

Step-by-step explanation:

3 0
3 years ago
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Jenny will owe her $9.30
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