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2 years ago

How does work affect energy between objects so it can cause a change in the form of energy?

Physics

2 answers:

mihalych1998 [28]2 years ago

5 0

Answer:

Doing work' is a way of transferring energy from one object to another, energy is transferred when a force moves through a distance.

Explanation: So more energy, more work done bc u transferred more energy to move the object and doing the work. and if you only use a little of energy, the work done also only a little.

sergey [27]2 years ago

5 0

Answer:

Work transfers energy.

Explanation:

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The current in a hair dryer measures 11 amps. The resistance of the hair dryer is 15 ohms. What is the voltage? Your Answer: Que

lorasvet [3.4K]

V=IR
V=15x11
V=165ohms

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Ohms law

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2 years ago

A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .if after the collision it moves with a velocity of 2

ch4aika [34]

Answer:

-1.2 kg - m/s

Explanation:

$\pink{\frak{Given}}\begin{cases}\textsf{ A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .}\\\textsf{ After the collision it moves with a velocity of 2.0m/s in the opposite direction.}\end{cases}$

And we need to find out the change in momentum of the body . Here ,

velocity before collision (u) = 10m/s
velocity after collision (v) = 2m/s .

We know that momentum is defined as amount of motion contained in a body . Mathematically ,

$\sf\longrightarrow momentum (p)= mass(m) * velocity(v)$

Therefore change in momentum will be,

$\sf\longrightarrow \triangle p = mv - mu$

Since the direction of velocity changes after the collision , the velocity will be -2m/s .

$\sf\longrightarrow \Delta p = 100g( -2m/s -10m/s) \\$

$\sf\longrightarrow \Delta p =\dfrac{100}{1000}kg ( -12m/s) \\$

$\sf\longrightarrow \Delta p = 0.1 kg * -12m/s \\$

$\sf\longrightarrow \boxed{\bf \Delta p = -1.2 \ kg-m/s} \\$

7 0

1 year ago

20. Which statement is false? Rewrite it so that it is true. a. Fusion involves the combination of two smaller atoms into a larg

Annette [7]

Answer:

c. Fission and fusion are two processes that release very little amounts of energy.

Explanation:

This statement is false. In fact, both fission and fusion are processes which release very large amounts of energy. The statement can be rewritten as it is true as follows:

"Fission and fusion are two processes that release very large amounts of energy."

Fission occurs when a large nucleus break apart, splitting into smaller nuclei, while fusion occurs when two light nuclei combine together into a larger nucleus. In both cases, the mass of the reactants is larger than the mass of the final products, so some of the mass has been converted into energy, according to Einstein's equation:

$E = \Delta m c^2$

where

E is the energy released

$\Delta m$ is the mass lost in the process

c is the speed of light

Since c is a very large number ( $c=3\cdot 10^8 m/s$ ), we see that even a very small mass $\Delta m$ causes the released of a huge amount of energy, so both fission and fusion release large amounts of energy.