Use this equation
Distance(s)=speed(v)•time(t)
Given,req-soln
1.
S=10cm=0.1m
t=4sec
V=s/t=>0.1•10/4•10=>1/40=0.025
2.
V=0.1m/s
t=1.5 sec
S=vt =0.1•1.5=0.15
The US is the answer I think
Explanation:
Step one:
given dara
mass of ball m=0.kg
initial velocity u= 10 m/s
final velocity v=10m/s
Required
momentum before and after impact
the expression for momentum P
P=mv
before impact
P=mv
P1=0.5*10
P1=5(kg⋅m/s)
after impact
P=mu
P2=0.5*10
P2=5(kg⋅m/s)
change in momentum is =P1-P2= 5-5=0
yes, momentum is conserved.
Explanation:
2. Sum the torques about the fulcrum.
(450 N) (2 m) − (350 N) x = 0
x = 2.57 m
3. Sum the torques about the fulcrum.
(3600 N) (0.20 m) − F (0.90 m) = 0
F = 800 N
Mechanical advantage is the ratio between the load force and effort force.
MA = 3600 N / 800 N
MA = 4.5
Velocity ratio is the mechanical advantage divided by efficiency. Assuming the lever is 100% efficient:
VR = 4.5 / 1
VR = 4.5
4. Mechanical advantage is the ratio between the load force and effort force.
MA = 900 N / 600 N
MA = 1.5
The velocity ratio is the distance moved by the effort divided by the distance moved by the load. For a 3 pulley system, VR = 3.
Efficiency is mechanical advantage divided by velocity ratio.
e = 1.5 / 3
e = 0.50
5. Sum the torques about the fulcrum.
(-300 N) (0.10 m) + F (0.03 m) = 0
F = 1000 N