All objects within a closed system tend to move

There is a bell at the top of a tower that is 95 m high. The mass of the bell is 21 kg. What is the potential energy of the bell

melomori [17]

Answer:

19,551 J!

Explanation:

The formula is PE = ham (h=height, a= acceleration or 9.8, m= mass)

PE = (95)(9.8)(21)

PE = 19,551 Joules

5 0

3 years ago

Is the capacity or potential to influence?

Ira Lisetskai [31]

POWER is the capacity or potential to influence others.

6 0

2 years ago

URGENT WORTH 30 POINTS!!

olchik [2.2K]

Answer:

1. It won't break

2. 0.5 squared meters

Explanation:

1. Pressure (P) is force (F) exerted over an area(A). Greater the force or smaller the area, the pressure will be greater. This is presented by an equation:

P = F / A

This metallic object can be placed on the table in 3 different positions, depending on which its side is pressed against the table. Since its dimensions are 3 • 6 • 8 m, surface areas of these sides are:

A1 = 3 • 6 = 18m^2

A2 = 3 • 8 = 24m^2

A3 = 6 • 8 = 48m^2

It is already stated that the smaller are, greater the pressure, so this object will exert the greatest pressure if it's placed on the table with its 18m^2 side. In this case, pressure will be:

P = 400N / 18m^2

P = 22.2 N/m^2 (N/m^2 is the same unit as Pascal)

So, the table can withstand 250 Pa of pressure, the object exerts only 22.2 Pa, which means that the glass table won't break.

2. Again, we need to know the equation that connects the force and the pressure, and that is:

P = F / A

In this case, we have both the force and the pressure, and we want to find the surface of the area. From the previous equation, area can be found as:

A = F / P

A = 20N / 40Pa (N/m^2)

A = 0.5 m^2

So, the answer is: this pressure is exerted on the area of half of squared metar.

8 0

2 years ago

A conservative force F⃗ is in the +x-direction and has magnitude F(x)=α/(x+x0)2, where α=0.800N.m2 and x0=0.200m. (a) What is th

sashaice [31]

Answer:

U=α/(x+x_0)^2

v=1.88m/s

Explanation:

We have that

$F(x)=\frac{\alpha}{(x+x_0)^2}\\\alpha=0.800Nm^2\\x_0=0.200m$

(a)

The potential is calculated by using

$U=-\int Fdx=-\int \frac{\alpha}{(x+x_0)^2}dx\\U=\frac{\alpha}{(x+x_0)}$

(b)

m=0.5kg

The acceleration can be obtained if we calculate the force for x=4, and after we compute the acceleration

$F(0.4)=\frac{0.8Nm^2}{(0.4m+0.2m)^2}=2.22N\\F=ma\\2.22N=(0.5kg)a\\a=4.44\frac{m}{s^2}$

and finally, we can use the equation for the final speed

$v^2=v_0^2+2ax\\\\v=\sqrt{(0)+2(4.44\frac{m}{s^2})(0.4m)}\\\\v=1.88\frac{m}{s}$

I hope this is useful for you

regards

5 0

3 years ago

If you went up in an elevator to the top of a 50m building then came back down, determine these quantities:

ehidna [41]

If you walked into the building with your cup of coffee at 8:00 in the morning, took a ride up and down on the elevator for fun, and then went home, then ...

When you got to the top:

... Your distance covered = 50 meters

... Your displacement since you started = 50 meters up

When you returned to the bottom:

... Your total distance covered = 100 meters

... Your displacement since you started = zero

7 0

3 years ago

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