All objects within a closed system tend to move

A piece of wood on top of an ocean wave stays in the same location, only moving up and down as the wave passes. It is energy tha

Ierofanga [76]

Answer:

Hey

Yes, this is true.

As some people have it wrong, waves in the water (ocean) are not waves of moving water, rather the wave is moving through the water. A wave is a disturbance of a medium not the meduim moving.

8 0

3 years ago

Which change would result in a stronger electromagnet?

Sonbull [250]

I'd say B.) Increasing the voltage of the battery.

6 0

3 years ago

Read 2 more answers

Compare and contrast the life cycle of a low mass star and a high mass star

True [87]

Low mass: Live for billions (trillions?) of years. The first low mass red dwarfs in this universe still haven't died off yet, so we aren't completely sure what happens when they "die."

<span>Very High Mass: Run through their fuel exceedingly fast. *Die* relatively quickly (in the range of tens to hundreds of millions of years instead of billions and beyond) and go out with style, Supernova that will leave behind a neutron star (the *kind of very high mass stars" end this way) or a black hole (the *very very high mass stars* end this way.)</span>

6 0

3 years ago

The 88-lb force P is applied to the 210-lb crate, which is stationary before the force is applied. Determine the magnitude and d

Marina86 [1]

Answer:

$F=-88Ib$

Explanation:

From the question we are told that:

Force P=88Ib

Mass of crate M_c=210Ib

Generally the equation for Frictional force F is mathematically given by

$Friction\ force (f) = friction\ coefficient\ (u) * Normal\ reaction (N)$

$F=u*N$

with $\mu =0.47$

$F=98.7Ib$

Therefore since Static Friction supersedes applied force body remains at rest.

Frictional force =88Ib (negative)

$F=-88Ib$

5 0

3 years ago

A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800.0 N on him. Th

ipn [44]

Answer:

a) $F_{fric}$ = 692 N

b) $F_{applied}$ = 932 N

Explanation:

a)

According to newton's second law of motion, acceleration of an object is directly proportional to the net force acting on it. When there is no net force force acting on the body, there is no acceleration. A force is a push or a pull, and the net force ΣF is the total force, or sum of the forces exerted on an object in all directions.

$F_{net}$ ∝ a

$F_{net}$ = ma

$F_{applied} - F_{fric}$ = ma

Given data:

$F_{applied}$ = 800 N

Mass = m = 90 kg

acceleration = a = 1.2 m/s²

$F_{fric}$ = ?

800 - $F_{fric}$ = (90)(1.2)

$F_{fric}$ = 692 N

b)

According to newton's second law of motion,

$F_{net}$ ∝ a

$F_{net}$ = ma

$F_{applied} - F_{fric}$ = ma

Given data:

If we assume the same friction and acceleration between player's feet and ground as calculated in part a

$F_{fric}$ = 692 N

acceleration = a = 1.2 m/s²

We take the equal mass to the total mass of both the players because when the winning player push losing player backward, he exert force on the ground not only due to his mass but also due to the mass of losing player.

Mass = M = m₁ + m₂ = 110 kg + 90 kg

= 200 kg

$F_{applied}$ = ?

$F_{applied}$ - 692 N = (200)(1.2)

$F_{applied}$ = 692 + 240

$F_{applied}$ = 932 N

7 0

4 years ago