We have that the instantaneous velocity of the
shuttlecock when it hits the ground is
From the question we are told
Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the
shuttlecock when it hits the ground? Show your work below.
Generally the equation for acceleration is mathematically given as
Where
acceleration is still -9.81 m/s2,
Hence,
Therefore
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Answer:
80 Ω.
Explanation:
In this circuit the resistances are in series.The equivalent resistance of a series circuit is equal to the sum of the resistances. Req= 60 + 20 = 80 Ω.
Answer:
Increasing the speed of an object decreases its motion energy. Increasing the speed of an object increases its motion energy. Increasing the speed of an object does not affect its motion energy. Whether or not its motion energy is affected depends on how much its speed was increased.
Explanation:
Answer:
699.67ft
Explanation:
We are given with,
- α = 1.2×10⁻⁵ / °C
- L₀ = 700 ft
- ΔT = -10°C − 30°C = -40°C
Now, We have to find ΔL:
- ΔL = (1.2×10⁻⁵ / °C) (700 ft) (-40°C)
- ΔL = −0.336
Rounded to two significant figures, the change in length is −0.33ft.
<u>Therefore, the final length is approximately 700 ft − 0.33 ft = 699.67ft</u>.
Potassium iodide
Molar mass: 166.0028 g/mol
Formula: KI
