1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aalyn [17]
3 years ago
6

How can you increase the momentum of an object?

Physics
1 answer:
aniked [119]3 years ago
3 0
Hope this helps, have a great day ahead!

You might be interested in
In graphing enthalpy entropy and state changes which two variables are included ? A. volume and temperature B. amount of heat ad
Blababa [14]

In graphing enthalpy entropy and state changes the two variables that are included are amount of heat added and pressure. The answer is letter D. The rest of the choices do not answer the question above.

7 0
4 years ago
Read 2 more answers
What is my purpose?
castortr0y [4]
As Rene Descartes - french mathematician of Cartesian graphs - said "Cogito ergo sum". I think, therefore I am. 
This can be adapted to I think therefore I am, I think ... as a "geeky joke".
8 0
3 years ago
21.-Una esquiadora olímpica que baja a 25m/s por una pendiente a 20o encuentra una región de nieve húmeda de coeficiente de fric
jeyben [28]

Answer:

y = 12.82 m

Explanation:

We can solve this exercise using the energy work theorem

          W = ΔEm

friction force work is

          W = fr . s = fr s cos θ

the friction force opposes the movement, therefore the angle is 180º

           W = - fr s

we write Newton's second law, where we use a reference frame with one axis parallel to the plane and the other perpendicular

           N -Wy = 0

           N = mg cos θ

the friction force remains

            fr = μ N

            fr = μ mg cos θ

             

work gives

           W = - μ mg s cos θ

initial energy

           Em₀ = ½ m v²

the final energy is zero, because it stops

we substitute

          - μ m g s cos θ = 0 - ½ m v²

          s = ½ v² / (μ g cos θ)

         

let's calculate

          s = ½ 20² / (0.55 9.8 cos 20)

          s = 39.49 m

this is the distance it travels along the plane, to find the vertical distance let's use trigonometry

            sin 20 = y / s

           y = s sin 20

           y = 37.49 sin 20

           y = 12.82 m

8 0
4 years ago
Object 1 has a mass of 3m and is moving to the right at a velocity of
andrew11 [14]

Answer:

In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

6 0
3 years ago
Two astronauts, each with a mass of 50 kg, are connected by a 7 m massless rope. Initially they are rotating around their center
kiruha [24]

Answer:

The angular  velocity is w_f =  1.531 \ rad/ s

Explanation:

From the question we are told that

     The mass of each astronauts is  m =  50 \ kg

      The initial  distance between the two  astronauts  d_i  =  7 \  m

Generally the radius is mathematically represented as r_i  =  \frac{d_i}{2} = \frac{7}{2}  =  3.5 \  m

      The initial  angular velocity is  w_1 = 0.5 \  rad /s

       The  distance between the two astronauts after the rope is pulled is d_f =  4 \  m

Generally the radius is mathematically represented as r_f  =  \frac{d_f}{2} = \frac{4}{2}  =  2\  m

Generally from the law of angular momentum conservation we have that

           I_{k_1} w_{k_1}+ I_{p_1} w_{p_1} = I_{k_2} w_{k_2}+ I_{p_2} w_{p_2}

Here I_{k_1 } is the initial moment of inertia of the first astronauts which is equal to I_{p_1} the initial moment of inertia of the second astronauts  So

      I_{k_1} = I_{p_1 } =  m *  r_i^2

Also   w_{k_1 } is the initial angular velocity of the first astronauts which is equal to w_{p_1} the initial angular velocity of the second astronauts  So

      w_{k_1} =w_{p_1 } = w_1

Here I_{k_2 } is the final moment of inertia of the first astronauts which is equal to I_{p_2} the final moment of inertia of the second astronauts  So

      I_{k_2} = I_{p_2} =  m *  r_f^2

Also   w_{k_2 } is the final angular velocity of the first astronauts which is equal to w_{p_2} the  final angular velocity of the second astronauts  So

      w_{k_2} =w_{p_2 } = w_2

So

      mr_i^2 w_1 + mr_i^2 w_1 = mr_f^2 w_2 + mr_f^2 w_2

=>   2 mr_i^2 w_1 = 2 mr_f^2 w_2

=>   w_f =  \frac{2 * m * r_i^2 w_1}{2 * m *  r_f^2 }

=>    w_f =  \frac{3.5^2 *  0.5}{  2^2 }

=>   w_f =  1.531 \ rad/ s

       

3 0
3 years ago
Other questions:
  • Look at the picture below. The boy is swinging back and forth on the swing. At which point is the potential energy of a swing th
    13·2 answers
  • If an unknown element has a mass number of 14 and you are told that it has 7 neutrons how many protons dose it have
    13·1 answer
  • Identify the possible source of earth's magnetic field
    15·1 answer
  • Suppose you were bungee jumping from a bridge while blowing a hand-held air horn. How would someone remaining on the bridge hear
    5·2 answers
  • An oxygen atom picks up two additional, free-floating electrons. Is the charge of the newly formed oxygen ion positive, negative
    13·1 answer
  • A vehicle moving along at 5m/s. What should be the constant deceleration in order to stop it within 15m?​
    10·1 answer
  • What is the measure of the average kinetic energy of the particles in a material known as?
    10·1 answer
  • What is agrculture and it means​
    12·1 answer
  • When you walk across the ground and push on it with your feet...
    15·2 answers
  • For a fixed amount of gas at a fixed temperature, what will happen if the volume is doubled?.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!