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aalyn [17]
3 years ago
6

How can you increase the momentum of an object?

Physics
1 answer:
aniked [119]3 years ago
3 0
Hope this helps, have a great day ahead!

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Change in speed over a given period of time is
madam [21]

Explanation:

Acceleration is the change in speed over a given time period

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3 years ago
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Using the definition of moment of inertia, calculate icm, the moment of inertia about the center of mass, for this object.
Step2247 [10]
<span> The masses have no inertia about their own CM, and "the object" is the two masses. </span>
<span>1. Icm (at point A) = 2mr^2 
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3 0
3 years ago
Below is a circuit schematic of sources and resistors (Figure 3). VS = 10V , R1 = 100Ω, R2 = 50Ω, R3 = 25Ω, IS = 2A. Calculate t
lorasvet [3.4K]

Answer:

V_3\approx 4.28\,\,V

I_1=0.0572\,\,amps

I_3\approx 0.171\,\,amps

Explanation:

Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.

So we first find the equivalent resistance for the two resistors in parallel:

\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega

By knowing this, we can estimate the total current through the circuit,:

Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps

So approximately 0.17  amps

and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

So now we know that the potential drop across the parellel resistors must be:

10 V -  4.28 V = 5.72 V

and with this info, we can calculate the current through R1 using Ohm's Law:

I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps

4 0
4 years ago
A wire carrying a current is shaped in the form of a circular loop of radius 3.0mm If the magnetic field strength that this curr
ahrayia [7]

Answer:

Current, I = 5.3 A

Explanation:

It is given that,

Radius of circular loop, r = 3 mm = 0.003 m

Magnetic field strength, B = 1.1 mT = 0.0011 T

We need to find the magnitude of the current that flows through the wire. The magnetic field for a current carrying wire is given by :

B=\dfrac{\mu_o I}{2r}

I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 0.0011\ T\times 0.003\ m}{4\pi\times 10^{-7}}

I = 5.25 A

or

I = 5.3 A

So, the magnitude of the current that flows through the wire is 5.3 A. Hence, this is the required solution.

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4 years ago
Give an example of a food chain with at least 3 organisms
givi [52]
Grass-grasshopper-bluebird-snake-owl
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