Answer:
A principle of material science which expect that bunches of particles delivered by development of electrons adjust themselves in bunches (called "spaces") in attractive materials. The heading of attractive field at a point is the heading to which a free north shaft would move in the event that set at that point within the field.
Avogadro's number is equal to 6.02 E 23
Thie means we have 6.02 E 23 marshmallows.
Assuming each marshmallow to be a small cylinder we can calculate the area of its base
Area circumference = pi*r² = pi * (0.635/2)² = 0.317 cm²
So, 6.02 E 23 marshmallows * 0.317 cm² cover a total area of
Area covered = 1.908 E 23 cm² = 1.908 E 13 km²
<span>The land area of california is 1.560 E 5 mi</span>² = 4.04 E 5 km²
If we divide the Areas >>>>
1.908 E 13 km² / 4.04 E 5 km² = 47. 227 E 6 (This is the number of times the area of California could be filled with those marshmallows)
Now for the height, we multiply this number times the height of each marshmallow
47. 227 E 6 * 2.54 cm = 119.96 E 6 cm = 1199.6 km above the surface
Answer:
355 m/s
Explanation:
Distance = 605 km
Initial speed =
= 284 m/s
Final velocity =
= 426 m/s
Average speed = ?
There is two method two find average speed. In first method, using 3rd equation of motion, we find acceleration.
![2as = v_{f}^{2}+v_{i}^{2}](https://tex.z-dn.net/?f=2as%20%3D%20v_%7Bf%7D%5E%7B2%7D%2Bv_%7Bi%7D%5E%7B2%7D)
Then using first equation of motion, we find time
![v_{f} = v_{i}+at](https://tex.z-dn.net/?f=v_%7Bf%7D%20%3D%20v_%7Bi%7D%2Bat)
Then using the formula of average velocity, we find average velocity
![v_{avg}=\frac{total-distance}{total-time}](https://tex.z-dn.net/?f=v_%7Bavg%7D%3D%5Cfrac%7Btotal-distance%7D%7Btotal-time%7D)
Second method is very simple
![v_{avg}=\frac{v_{f}+v_{i} }{2}](https://tex.z-dn.net/?f=v_%7Bavg%7D%3D%5Cfrac%7Bv_%7Bf%7D%2Bv_%7Bi%7D%20%7D%7B2%7D)
![v_{avg}=\frac{426+284}{2}](https://tex.z-dn.net/?f=v_%7Bavg%7D%3D%5Cfrac%7B426%2B284%7D%7B2%7D)
355 m/s