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3 years ago

If gravity between the sun and Earth suddenly vanished; describe the expected Earth motion.

Physics

1 answer:

Daniel [21]3 years ago

6 0

Answer:

When the gravity between the Sun and the Earth suddenly vanishes, then Earth will keep moving in a straight line in a direction where it was moving at the moment when gravity vanished.

Explanation:

The gravitational force between Sun and Earth is given by

$F = G\frac{M_{1}M_{2} }{R^{2}}$

Where F is the gravitational force between the Sun and the Earth. M₁ and M₂ are the masses of Sun and Earth and R is the distance between them.

If we assume that the gravity between the sun and Earth suddenly vanishes, then there would not be any force between the Sun and the Earth and the Earth will keep on moving in a straight line. This is endorsed by the Newton's first law that a body in motion remains in motion if no external force is acting on it.

The direction of Earth's motion will be determined by the previous direction of the motion that is the moment when the gravity was vanished.

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Parallel rays of monochromatic light with wavelength 583 nm illuminate two identical slits and produce an interference pattern o

romanna [79]

Answer:

I = 2.18 10⁻⁴ W / m²

Explanation:

The two-slit interference pattern is described by the expression for constructive interference.

d sin θ = m λ

If we also want to know the distribution of intensities we must perform the su of the electric field of the two waves, and find the intensity as the square of the velvet field, obtaining the expression

I = I_max cos² ((π d /λ L) y)

where d is the separation of the slits, λ the wavelength, L the distance to the screen e and the separation of the interference line with respect to the central maximum

let's reduce the magnitudes to the SI system

λ = 583 nm = 583 10⁻⁹ m

L = 75.0 cm = 75.0 10⁻² m

d = 0.640 mm = 0.640 10⁻³ m

y = 0.900 mm = 0.900 10⁻³ m

let's calculate the intensity of this line

I = 5 10⁻⁴ cos² ((π 0.640 10⁻³ /583 10⁻⁹ 0.75 10⁻²) 0.900 10⁻³)

I = 5 10⁻⁴ cos2 (413.84)

I = 5 10⁻⁴ 0.435

I = 2.18 10⁻⁴ W / m²

7 0

3 years ago

The San Andreas fault is a great example of a zone where _____ metamorphism is occurring.

Nadya [2.5K]

<span>dynamic

Hope this helps!</span>

5 0

4 years ago

Read 2 more answers

A planet of mass m moves around the Sun of mass M in an elliptical orbit. The maximum and minimum distance of the planet from th

zzz [600]

Answer:

the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

Explanation:

Given the data i the question;

mass of sun = M

minimum and maximum distance = r1 and r2 respectively

Now, using Kepler's third law,

" the square of period T of any planet is proportional to the cube of average distance "

T² ∝ R³

average distance a = ( r1 + r2 ) / 2

we know that

T² = 4π²a³ / GM

T² = 4π² [( ( r1 + r2 ) / 2 )³ / GM ]

T² = 4π² [( ( r1 + r2 )³ / 8 ) / GM ]

T² = 4π² [( r1 + r2 )³ / 8GM ]

T = √[ 4π² [( r1 + r2 )³ / 8GM ] ]

T = 2π √[( r1 + r2 )³ / 8GM ]

Therefore, the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

5 0

3 years ago

1. During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the tre

Grace [21]

Initial velocity u = 40
Angle at launch = 55 degrees
At maximum height v = 0, velocity equation v^2 = u^2 - 2gh,
0 = (40 x sin55)^2 - 2 x 9.81 x h => (40 x 0.819)^2 = 19.62h => h = 32.76^2 /
19.62
Maximum height = 54.7 m
We have v = u - gt => 0 = (40 x sin55) - 9.81 x t => t = 32.76 / 9.81 => t =
3.34 s
Time taken to hit the ground is 2t = 2 x 3.34 = 6.68 s
Distance from castle to trebuchet = utcos55 = 40 x 6.68 x 0.573 = 153.1 m

8 0

4 years ago

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Paraphin [41]

Answer:

a. Zombie

Explanation:

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4 years ago