The main factor that determines the stages a star will follow after the main sequence is the star's mass or size.
<h3>What is main sequence?</h3>
The main sequence of a star is a stage in the life cycle of that star. During the main sequence ( also called the zero age ), the star generates energy by nuclear fusion of Hydrogen atoms at the core of the star into Helium atoms. Eventually, the star runs out of hydrogen atoms, which concludes the main sequence. What happens afterward depends on the size of the star.
<h3>Low mass stars </h3>
For low-mass stars ( stars that are less than 0.1 times the mass of the sun), they slowly collapse into white dwarfs. These stars do not get hot enough to fuse helium atoms, instead hydrogen fusion continues until the whole star is filled with helium and slowly collapses into a white dwarf while it grows dimmer and colder.
<h3>Medium-sized stars</h3>
Medium-sized stars ( stars about 0.6 - 10 times the mass of our sun) become red giants. Stars similar in size to our sun are hot enough to fuse helium atoms, so towards the end of the main sequence it starts to fuse helium atoms, forming heavier elements like carbon and oxygen. The heavier elements move to the star's core due to gravity, while lighter elements like hydrogen form a shell around the core. This causes the sun to then grow in size, forming a red giant.
<h3>Large stars</h3>
Massive stars ( greater than 10 times the mass of the sun) and super-massive stars ( more than 40 times the mass of the sun ) end up exploding into a supernova , while the dense core collapses into a neutron star or a black hole.
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Yes it does ! Uh huh. Right you are. Truer words are seldom written.
You have quoted the law quite accurately but also incompletely.
Do you have a question to ask ?
Heat always transfers from substances with high thermal energy to substances with low thermal until both substances reach the maximum temperature
(a) -2451 N
We can start by calculating the acceleration of the car. We have:
is the initial velocity
v = 0 is the final velocity of the car
d = 125 m is the stopping distance
So we can use the following equation
To find the acceleration of the car, a:
Now we can use Newton's second Law:
F = ma
where m = 1100 kg to find the force exerted on the car in order to stop it; we find:
and the negative sign means the force is in the opposite direction to the motion of the car.
(b) 
We can use again the equation
To find the acceleration of the car. This time we have
is the initial velocity
v = 0 is the final velocity of the car
d = 2.0 m is the stopping distance
Substituting and solving for a,
So now we can find the force exerted on the car by using again Newton's second law:
As we can see, the force is much stronger than the force exerted in part a).
C is what i always have so ima go with C.
