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Scorpion4ik [409]
3 years ago
13

A small aircraft flies a 2160-mi round trip in a 45 mi/h wind. Find the average rate of speed for the trip if the aircraft can f

ly 225 mi/h with no wind.
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0

9514 1404 393

Answer:

  216 mi/h

Step-by-step explanation:

The time for the trip with the wind is ...

  (1080 mi)/(225 +45 mi/h) = 4 h

The time for the trip against the wind is ...

  (1080 mi)/(225 -45 mi/h) = 6 h

The average speed for the entire round trip is ...

  (2160 mi)/(4 +6 h) = 216 mi/h

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victus00 [196]

Answer:

x-intercepts:  (-1, 0) and (2, 0)

x-intercept:  (-3, 0)

Step-by-step explanation:

Given <u>quadratic function</u>:

f(x)=-4x^2+4x+8

The <u>x-intercepts</u> of a <u>quadratic function</u> are the points at which the curve <u>crosses the x-axis</u> ⇒ when y = 0

Therefore, to find the x-intercepts of the given function, set the function to zero:

\implies -4x^2+4x+8=0

Factor out -4:

\implies -4(x^2-x-2)=0

Divide both sides by -4

\implies x^2-x-2=0

Rewrite the middle term as -2x + x:

\implies x^2-2x+x-2=0

Factor the first two terms and the last two terms separately:

\implies x(x-2)+1(x-2)=0

Factor out the common term (x - 2):

\implies (x+1)(x-2)=0

<u>Zero Product Property</u>:  If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the <u>Zero Product Property</u>, set each factor equal to zero and solve for x (if possible):

\begin{aligned}(x+1) & = 0 & \quad \textsf{ or } \quad \quad (x-2) & = 0\\\implies x & = -1 & \implies x & = 2\end{aligned}

Therefore, the x-intercepts are (-1, 0) and (2, 0).

---------------------------------------------------------------------------------------

Given <u>quadratic equation</u>:

-9 = x^2 + 6x

Add 9 to both sides:

\implies x^2+6x+9=0

Rewrite the middle term as 3x + 3x:

\implies x^2+3x+3x+9

Factor the first two terms and the last two terms separately:

\implies x(x+3)+3(x+3)=0

Factor out the common term (x + 3):

\implies (x+3)(x+3)=0

\implies (x+3)^2=0

Square root both sides:

\implies (x+3)=0

Solve for x:

\implies x=-3

Therefore, the x-intercept is (-3, 0).

As the function has a <u>repeated factor</u> (multiplicity of two), the curve will touch the x-axis at (-3, 0) and bounce off.  

3 0
2 years ago
How do you solve <br>m=q/z-v solve for z
g100num [7]
Hello!

To solve whatever z is we have to get it by itself by using inverse operations. I will undo operations below.

m=q/z-v+v
m+v=q/z(z)
m+v+z=q
m+v+z-z=q-z
m+v=q-z
Here I will switch z to adding negative z so we can use the commutative property.
m+v= q+(-z)
m+v=-z +q
m+v-q=-z+q-q
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We now have our formula for z. z=m+v-q. Hope this helps!

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Answer: 7 days.

Step-by-step explanation:

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Then, Number of days he spent in New Zealand = 3x

and number of days he spent in India = x+5

According to the question we have the following eqauation,

x+3x+x+5=40\\\\\Rightarrow\ 5x+5=40\\\\\Rightarrow\ 5x=40-5\\\\\Rightarrow\ 5x=35\\\\\Rightarrow\ x=\dfrac{35}{5}=7

Hence, he spent 7 days in Australia.

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Ilia_Sergeevich [38]

Answer:

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