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I am Lyosha [343]
3 years ago
7

Which statement is true for light passing into a medium that is less optically dense than the first medium through which it pass

ed?
The index of refraction of the second medium is higher.


The index of reflection of the second medium is lower.


The index of reflection of the second medium is higher.


The index of refraction of the second medium is lower.
Physics
2 answers:
BigorU [14]3 years ago
5 0

Answer:

The correct option is;

The index of refraction of the second medium is lower

Explanation:

The index of refraction of a material indicates the magnitude of the optical density of a material. The index of refraction or the refractive index, n, are indices (ratio) of the speed of light through an optically dense medium relative to the speed of light through a vacuum.

The definition of the refractive index is the number of times light travelling through a medium would be slower than light travelling through vacuum

Therefore, the index of refraction of a second medium that is less optically dense than a first medium from which light originates and travels through it would be lower than the index of refraction of the first medium

AleksAgata [21]3 years ago
5 0

Answer:

D

Explanation:

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Answer:

91.017N

Explanation:

Parameters

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so N= no of trips = 8, From  Wave speed(V) = N *L/t , we have :

V= 8*4.67/0.794 = 47.0529 m/s.

We compute the cords mass per length,  Let it be P

P = M/L = 0.192/4.67 = 0.04111 kg/m

From  T = P * V^2  where T = Tension, we have

T = 0.04111 * (47.0529)^2

T =  91.017N.

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3 years ago
The rope of a swing is 3.10 m long. Calculate the angle from the vertical at which a 76.0 kg man must begin to swing in order to
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Answer:

The angle from the vertical is 48.72°

Explanation:

Given :

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According to conservation law,

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   \frac{1}{2} M v^{2} = mgh

We calculate height,

   h = \frac{M v^{2} }{2mg}

   h = \frac{1520(1.01)^{2} }{2\times 75 \times 9.8}                      ( ∵ g = 9.8 \frac{m}{s^{2} } )

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This is the distance of the rope at the bottom,

So we take difference of it.

⇒ 3.10 - 1.05 = 2.05

We can calculate angle between them,

\cos \theta = \frac{2.05}{3.10}  = 0.6597

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