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seropon [69]
3 years ago
10

For the following integral, give a power or simple exponential function that if integrated on a similar infinite domain will hav

e the same convergence or divergence behavior as the given integral, and use that to predict whether the integral converges or diverges. Note that for this problem we are not formally applying the comparison test; we are simply looking at the behavior of the integrals to build intuition.
∫(x+5)/x^3+7x+5 dx
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
5 0

Answer:

hello your question is incomplete attached below is the complete question

answer :

for  I1 =     \frac{1}{x^2} + \frac{4}{x^3}    The integral converges

for  I2 =    \frac{2x + 6}{2(x^2 + 6x + 4 )}  The integral diverges

for  I3 =  \frac{1}{x^2}  The integral converges

for  I4 = 1  The integral diverges

Step-by-step explanation:

The similar integrands and the prediction ( conclusion )

for  I1 =     \frac{1}{x^2} + \frac{4}{x^3}    The integral converges

for  I2 =    \frac{2x + 6}{2(x^2 + 6x + 4 )}  The integral diverges

for  I3 =  \frac{1}{x^2}  The integral converges

for  I4 = 1  The integral diverges

attached below is a detailed solution

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Convert 11.42424242 … to a rational expression in the form of a over b, where b ≠ 0.
babymother [125]

x =  11\frac{42}{99}

Step-by-step explanation:

11.42424242.... = 11. \overline{42} \\ let \: x = 11. \overline{42} .....(1)\\ 100x = 1142.\overline{42}....(2) \\ subtracting \: (1) \: from \:  (2) \: \\  100x - x = 1142.\overline{42} - 11. \overline{42} \\ 99x = 1131 \\ x =  \frac{1131}{99}  \\x =  11\frac{42}{99}  \\

3 0
3 years ago
1/2x+1/3y=5 and 1/4x+y=10 solve this system by substitution
qaws [65]

Answer:

  (x, y) = (4, 9)

Step-by-step explanation:

You can use the second equation to write an expression for y.

  y = 10 - 1/4x . . . . subtract 1/4x from the given 2nd equation

Now, substitute that for y in the first equation:

  1/2x + 1/3(10 -1/4x) = 5

  1/2x + 10/3 -1/12x = 5 . . . . eliminate parentheses

You can work this a couple of ways from here. One is to multiply by 12 to eliminate fractions. Another is to work with the numbers as they are. We'll do that, because we don't get enough practice doing arithmetic with fractions.

  5/12x = 5/3 . . . . . subtract 10/3

  x = (5/3)/(5/12) = 12/3 = 4

From above, we can use our expression for y:

  y = 10 - 1/4·4 = 9

The solution is (x, y) = (4, 9).

 

5 0
3 years ago
Simplify. <br><br> 54+4(34−12)2<br><br><br><br> Enter your answer in the box.
gtnhenbr [62]

Answer:

230

Step-by-step explanation:

54+4×22×2

54+88×2

54+176

230

3 0
3 years ago
Read 2 more answers
For the equation |ax+b|=c (where a,b, and c are real numbers and a≠0), what value of c results in exactly one solution?
Degger [83]

Step-by-step explanation:

Correct option is

D

a



=0,b



=0

The condition for ax+by+c=0 to be a linear eqaution in two variables is

a

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=0,b

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=0

7 0
2 years ago
In a certain region, about 6% of a city's population moves to the surrounding suburbs each year, and about 4% of the suburban po
Sedbober [7]

Answer:

City @ 2017 = 8,920,800

Suburbs @ 2017 = 1, 897, 200

Step-by-step explanation:

Solution:

- Let p_c be the population in the city ( in a given year ) and p_s is the population in the suburbs ( in a given year ) . The first sentence tell us that populations p_c' and p_s' for next year would be:

                                  0.94*p_c + 0.04*p_s = p_c'

                                  0.06*p_c + 0.96*p_s = p_s'

- Assuming 6% moved while remaining 94% remained settled at the time of migrations.

- The matrix representation is as follows:

                         \left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] \left[\begin{array}{c}p_c\\p_s\end{array}\right] =  \left[\begin{array}{c}p_c'\\p_s'\end{array}\right]          

- In the sequence for where x_k denotes population of kth year and x_k+1 denotes population of x_k+1 year. We have:

                         \left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] x_k = x_k_+_1

- Let x_o be the populations defined given as 10,000,000 and 800,000 respectively for city and suburbs. We will have a population x_1 as a vector for year 2016 as follows:

                          \left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] x_o = x_1

- To get the population in year 2017 we will multiply the migration matrix to the population vector x_1 in 2016 to obtain x_2.

                          x_2 = \left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right]\left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] x_o

- Where,

                         x_o =  \left[\begin{array}{c}10,000,000\\800,000\end{array}\right]

- The population in 2017 x_2 would be:

                         x_2 = \left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right]\left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] \left[\begin{array}{c}10,000,000\\800,000\end{array}\right] \\\\\\x_2 = \left[\begin{array}{c}8,920,800\\1,879,200\end{array}\right]

5 0
4 years ago
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