Answer:
Option c → Tert-butanol
Explanation:
To solve this, you have to apply the concept of colligative property. In this case, freezing point depression.
The formula is:
ΔT = Kf . m . i
When we add particles of a certain solute, temperature of freezing of a solution will be lower thant the pure solvent.
i = Van't Hoff factor (ions particles that are dissolved in the solution)
At this case, the solute is nonvolatile, so i values 1.
ΔT = Difference between fussion T° of pure solvent - fussion T° of solution.
T° fussion paradichlorobenzene = 56 °C
T° fussion water = 0°
T° fussion tert-butanol = 25°
Water has the lowest fussion temperature and the paradichlorobenzene has the highest Kf. But the the terbutanol, has the highest Kf so this solvent will have the largest change in freezing point, when all the molalities are the same.
Leeward, because adiabatic heating is faster on the leeward side than the windward side due to its non-saturated air descent.
Answer:
V₂ = 1592.32 L
Explanation:
Given data:
Initial number of moles = 1.54 mol
Initial volume = 383.2 L
Final volume = ?
Final number of moles = 6.4 mol
Solution:
Formula:
V₁/n₁ = V₂/n₂
V₁ = Initial volume
n₁ = initial number of moles
V₂ = Final volume
n₂ = Final number of moles
now we will put the values in formula.
V₁/n₁ = V₂/n₂
383.2 L / 1.54 mol = V₂/ 6.4 mol
V₂ = 248.8 L/mol ×6.4 mol
V₂ = 1592.32 L
Depends on the length of the Ant. If it's a millimeter long then the park would be 999,999mm longer than the ant. (I believe)
Choice ' D ' is the correct statement.