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iragen [17]
3 years ago
11

The specific rate constant, k, for radioactive beryllium–11 is 0.049 s–1. What mass of a 0.500 mg sample of beryllium–11 remains

after 28 seconds? This reaction was found to be first order.
Chemistry
1 answer:
Sonja [21]3 years ago
5 0

<u>Answer: </u>The mass of sample that remained is 0.127 mg

<u>Explanation:</u>

The integrated rate law equation for first-order kinetics:

k=\frac{2.303}{t}\log \frac{a}{a-x} ......(1)

Given values:

a = initial concentration of reactant = 0.500 mg

a - x = concentration of reactant left after time 't' = ?mg

t = time period = 28 s

k = rate constant = 0.049s^{-1}

Putting values in equation 1:

0.049s^{-1}=\frac{2.303}{28s}\log (\frac{0.500}{(a-x)})\\\\\log (\frac{0.500}{(a-x)})=\frac{0.049\times 28}{2.303}\\\\\frac{0.500}{a-x}=10^{0.5957}\\\\frac{0.500}{a-x}=3.94\\\\a-x=\frac{0.500}{3.942}=0.127mg

Hence, the mass of sample that remained is 0.127 mg

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