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Anika [276]
3 years ago
6

Write the balanced chemical equation for the following reaction. Phases are optional. Solid iron(I) oxide reacts with hydrogen g

as to form solid iron and liquid water. 2Fe+3H,Ol Fe,O,+ 3H2 â 2Fe+ 3H2O(I)
Chemistry
1 answer:
Sphinxa [80]3 years ago
5 0

Answer:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(l)

Explanation:

Hello!

In this case, when writing chemical reactions from the given names we must make sure we know the proper formula for each reacted and produced species; thus, since solid iron (III) oxide is Fe_2O_3, hydrogen gas is H_2, solid iron is Fe and liquid water is just H_2O, we can write:

Fe_2O_3(s)+H_2(g)\rightarrow Fe(s)+H_2O(l)

However, since different amount of atoms of iron, hydrogen and oxygen are present at each side of the equation, we balance it by adding the following coefficients to each molecule:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(l)

And now it is balanced with two iron atoms, three oxygen atoms and six hydrogen atoms at both reactants and products.

Best regards!

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The  moles  of  CaCO3  which  are  there  in  antacid  tablet  that  contain  0.515g  CaCO3  is  calculated  as  follows

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3 years ago
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When the pressure that a gas exerts
Savatey [412]
<h2>Hello!</h2>

The answer is:

When the pressure that a gas exerts  on a sealed container changes from

22.5 psi to 19.86 psi, the  temperature changes from 110°C to

65.9°C.

<h2>Why?</h2>

To calculate which is the last pressure, we need to use Gay-Lussac's law.

The Gay-Lussac's Law states that when the volume is kept constant, the temperature (absolute temperature) and the pressure are proportional.

The Gay-Lussac's equation states that:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

We are given the following information:

We need to remember that since the temperatures are given in Celsius degrees, we need to convert it to Kelvin (absolute temperature) before use the equation, so:

P_1=22.5Psi\\T_1=110\°C=110\°C+273.15=383.15K\\T_1=65.9\°C=65\°C+273.15=338.15K

Now, calculating we have:

\frac{P_1}{T_1}*(T_2)=P_2\\\\P_2=\frac{P_1}{T_1}*(T_2)=\frac{22.5Psi}{383.15}*338.15=19.86Psi

Hence, the final pressure is equal to 19.86 Psi.

Have a nice day!

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3 years ago
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The vapor pressure of CCl3F at 300 K is 856 torr. If 11.5 g of CCl F is enclosed in a 1.0-L container, will any liquid be pres-
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Answer:

Yes, there will be liquid present and the mass is 5.19 g

Explanation:

In order to do this, we need to use the equation of an ideal gas which is:

<em>PV = nRT (1)</em>

<em>Where:</em>

<em>P: Pressure</em>

<em>V: Volume</em>

<em>n: number of moles</em>

<em>R: gas constant</em>

<em>T: Temperature</em>

we know that the pressure is 856 Torr at 300 K. So, if we want to know if there'll be any liquid present, we need to calculate the moles and mass of the CCl3F at this pressure and temperature, and then, compare it to the initial mass of 11.5 g.

From (1), solving for moles we have:

<em>n = PV/RT (2)</em>

Solving for n:

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n = 1.13 * 1 / 0.082 * 300

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The molar mass of CCl3F reported is 137.37 g/mol so:

m = 0.0459 * 137.37

m = 6.31 g

Finally, this means that if we put 11.5 g of CCl3F in a container, only 6.31 g will become gaseous, so, this means it will be liquid present, and the mass is:

m = 11.5 - 6.31

m = 5.19 g

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