Question

Write the balanced chemical equation for the following reaction. Phases are optional. Solid iron(I) oxide reacts with hydrogen gas to form solid iron and liquid water. 2Fe+3H,Ol Fe,O,+ 3H2 â 2Fe+ 3H2O(I)

Answer 1

Answer:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(l)$

Explanation:

Hello!

In this case, when writing chemical reactions from the given names we must make sure we know the proper formula for each reacted and produced species; thus, since solid iron (III) oxide is $Fe_2O_3$, hydrogen gas is $H_2$, solid iron is Fe and liquid water is just $H_2O$, we can write:

$Fe_2O_3(s)+H_2(g)\rightarrow Fe(s)+H_2O(l)$

However, since different amount of atoms of iron, hydrogen and oxygen are present at each side of the equation, we balance it by adding the following coefficients to each molecule:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(l)$

And now it is balanced with two iron atoms, three oxygen atoms and six hydrogen atoms at both reactants and products.

Best regards!