The final volume of the methane gas in the container is 6.67 L.
The given parameters;
- <em>initial volume of gas in the container, V₁ = 2.65 L</em>
- <em>initial number of moles of gas, n₁ = 0.12 mol</em>
- <em>additional concentration, n = 0.182 mol</em>
The total number of moles of gas in the container is calculated as follows;
![n_t = 0.12 + 0.182 = 0.302 \ mol](https://tex.z-dn.net/?f=n_t%20%3D%200.12%20%2B%200.182%20%3D%200.302%20%5C%20mol)
The final volume of gas in the container is calculated as follows;
![PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1 n_2}{n_1} \\\\V_2 = \frac{2.65 \times 0.302}{0.12} \\\\V_2 = 6.67 \ L](https://tex.z-dn.net/?f=PV%20%3D%20nRT%5C%5C%5C%5C%5Cfrac%7BV%7D%7Bn%7D%20%3D%20%5Cfrac%7BRT%7D%7BP%7D%20%5C%5C%5C%5C%5Cfrac%7BV_1%7D%7Bn_1%7D%20%3D%20%5Cfrac%7BV_2%7D%7Bn_2%7D%20%5C%5C%5C%5CV_2%20%3D%20%5Cfrac%7BV_1%20n_2%7D%7Bn_1%7D%20%5C%5C%5C%5CV_2%20%3D%20%5Cfrac%7B2.65%20%5Ctimes%200.302%7D%7B0.12%7D%20%5C%5C%5C%5CV_2%20%3D%206.67%20%5C%20L)
Thus, the final volume of the methane gas in the container is 6.67 L.
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18)
a. Ra
d. Ag
19)
a. C
b. Br
c. Mg
20)
a. S
b. Br
c. O
Sorry wasn’t sure about some of them in #18
Hope the notes are helpful.
Answer:
The identity of an atom is determined my the number of <u>protons</u>. This is the <u>atomic number</u>.
The particle(s) found inside the nucleus are called <u>protons and neutrons</u>. Their combined mass is referred to as <u>the mass number</u>.
Isotopes have the same number of <u>protons</u>, but different number of <u>neutrons</u>.
Answer:
elements
Matter that has only one kind of atom is called an element. Gold, copper, oxygen, and mercury are examples of elements. Most matter is made up of two or more different kinds of atoms that are chemically combined. This kind of matter is called a compound.
Explanation:
Answer:
here it is
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