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sergey [27]
3 years ago
14

Seleect the acid-base reaction.

Chemistry
2 answers:
erastova [34]3 years ago
8 0

Answer:

<h2>hi</h2>

Explanation:

bye answer is I don't know lol

katrin2010 [14]3 years ago
7 0
C is the only one that makes sense
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Which of the following measurements is equal to 0.373 cL?
earnstyle [38]
1. is the correct answer

6 0
3 years ago
Chlorine has two stable isotopes, Cl-35 and Cl-37. If their exact masses are 34.9689 amu and 36.9695 amu, respectively, what is
natima [27]

Answer:

X(Cl-35) = 75.95% => Answer 'A'

Explanation:

34.9689·X(Cl-35) + 36.9695·X(Cl-37) = 35.45; X = fractional abundance

X(Cl-35) + X(Cl-37) = 1  ⇒  X(Cl-37) = 1 - X(Cl-25)

34.9689·X(Cl-35) + 36.9695(1 - X(Cl-35)) = 35.45

34.9689·X(Cl-35) + 36.9695 - 36.9695·X(Cl-35) = 35.45

Rearrange ...

36.9695·X(Cl-35) - 34.9689·X(Cl-35) = 36.9689 - 35.45

2.0006·X(Cl-35) = 1.5195

X(Cl-35) = 1.5195/2.0006 = 0.7595 fractional abundance

⇒ % abundance = 75.95%

3 0
3 years ago
Read 2 more answers
10. You are given 480 grams of the substance. It's molecular weight is 1440 g. How many
Mademuasel [1]

Answer:

3

Explanation:

6 0
3 years ago
Cyclohexene, a hydrocarbon, has a molar mass of 82.1 g/mole. if the combustion of 0.8300 g cyclohexene produces 0.9102 g h2o and
adelina 88 [10]

Answer is:  the molecular formula is C₆H₁₀.

Chemical reaction: C₆Hₓ + yO₂ → 6CO₂ + x/2H₂O.

m(H₂O) = 0.9102; mass of the water.

n(H₂O) = m(H₂O) ÷ m(H₂O)  

n(H₂O) = 0,9102 g ÷ 18 g/mol

n(H₂O) = 0,0505 mol.

From chemical reaction: n(H) = 2 · n(H₂O).

n(H) = 0.101 mol.

m(CO₂) = 2.668 g; mass of carbon dioxide.

n(CO₂) = 2.668 g ÷ 44 g/mol.

n(CO₂) = 0.0606 mol; amount of the substance.

n(CO₂) = n(C) = 0.0606 mol.

n(C) : n(H) = 0.606 mol : 0.101 mol.

n(C) : n(H) = 6 : 10; proportion of carbon and hydrogen atoms in cyclohexene.

8 0
3 years ago
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How does soil affect groundwater?
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Water infiltrates faster into soils that are mostly sand than into those that are mostly clay or silt. ... When the soil is completely saturated, additional water moves slowly down through the unsaturated zone to the saturated zone, replenishing or recharging the groundwater.
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