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Papessa [141]
4 years ago
7

Why does an equation need to be balanced? *

Chemistry
1 answer:
GrogVix [38]4 years ago
4 0

Answer:

I think the answer is c

Explanation:

:)

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The domain Archaea are unicellular prokaryotes and can be autotrophs or heterotrophs
nexus9112 [7]

Answer:

I think its true I dont really know

Explanation:

true

7 0
3 years ago
Given the following reaction: 3CuCl2(aq) 2Na3PO4(aq) --> Cu3(PO4)2(s) 6NaCl(aq) MM (g/mol) 134.45 163.94 380.58 58.44 If 285
nata0808 [166]

Answer:

227.78g of the precipitate are produced

Explanation:

Based on the reaction, 3 moles of CuCl2 produce 1 mole of Cu3(PO4)2 (The precipitate).

To solve this question we need to find the moles of CuCl2 added. With these moles and the reactio we can find the moles of Cu3(PO4)2 and its mass as follows:

<em>Moles CuCl2:</em>

285mL = 0.285L * (6.3mol / L) = 1.7955 moles CuCl2

<em>Moles Cu3(PO4)2:</em>

1.7955 moles CuCl2 * (1mol Cu3(PO4)2 / 3mol CuCl2) = 0.5985 moles Cu3(PO4)2

<em>Mass Cu3(PO4)2 -380.58g/mol-</em>

0.5985 moles Cu3(PO4)2 * (380.58g/mol) =

227.78g of the precipitate are produced

7 0
3 years ago
An experiment shows that a 250 ?ml gas sample has a mass of 0.430 g at a pressure of 736 mmhg and a temperature of 28 ?c.
dmitriy555 [2]
What we're looking for here is the gas sample's molar mass given its mass, pressure, volume, and temperature. Recalling the gas law, we have

PV = nRT or
n = \frac{PV}{RT}

where R is <span>0.08206 L atm / mol K, P is the given pressure, T is the temperature, and V is the volume.

Before applying the values given, it is important to make sure that they are to be converted to have consistent units with that of R. 
</span>
Thus, we have

P = 736/ 729 = 0.968 atm
T = 28 + 273.15 = 301.15 K
V = 250/1000 = 0.250 L

Now, applying these converted values into the gas law, we have

n = \frac{(0.968 atm)(0.250 L)}{(0.08206 L.atm/mol.K)(301.15 K)}
n = 0.00979 moles

Given that the mass of the sample is 0.430 g, we have

molar mass = \frac{mass}{number of moles} 
molar mass = \frac{0.430}{0.00979} = 43.9

Thus, the gas sample has a molar mass of 43.9 g/mol.
4 0
4 years ago
In order to perform a chemical reaction, 225 mL of 0.500 M lead (II) nitrate is required. How much 5.00 M stock solution is requ
vladimir1956 [14]

Answer:

what

Explanation:

what ````

4 0
3 years ago
3
Murrr4er [49]

Answer:

Look at the properties of Oxygen and Silicon - the two most abundant elements in the Earth's crust - by clicking on their symbols on the Periodic Table.

Explanation:

7 0
3 years ago
Read 2 more answers
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