What is the molarity of a HCl solution, if 28.6 mL of a 0.175 m NaOH solution is needed to neutralize a 25.0 mL sample of the HC

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3 years ago

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Katen [24] · Answer 1 · 2022-06-27T00:53:22+03:00

The molarity of the HCl solution needed to neutralize 28.6 mL of a 0.175 M NaOH solution is 0.2002 M

We'll begin by writing the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, NaOH (nB) = 1

Volume of base, NaOH (Vb) = 28.6 mL

Molarity of base, NaOH (Mb) = 0.175 M

Volume of acid, HCl (Va) = 25 mL

<h3>Molarity of acid, HCl (Ma) = ?</h3>

The molarity of the acid, HCl can be obtained as follow:

MaVa / MbVb = nA / nB

(Ma × 25) / (0.175 × 28.6) = 1

(Ma × 25) / 5.005 = 1

Cross multiply

Ma × 25 = 5.005

Divide both side by 25

Ma = 5.005 / 25

Therefore, the molarity of the acid, HCl needed for the reaction is 0.2002 M