All categories

3 years ago

PLZ I NEED HALP NOW LIKE RIGHT NOW

Mathematics

1 answer:

anzhelika [568]3 years ago

5 0

Answer:

C. (1,0)

Step-by-step explanation:

If he starts at his house (4,-2) and goes left 3 and up 3 he ends up at C. (1,0)

You might be interested in

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

HLEPPPPPP!!!!!

Ksenya-84 [330]

Answer:

Solutions:-5,0,9,6

Not solutions: 12.5,10

Explanation:

The inequality that was given is:

20 > 5 + 3x

First, group similar terms;

20 - 5 < 3x

15 < 3x

x = 5

Thus, the solutions are:-3.5, 5, 4 3/4, -15

The not solutions are:-10 2/3, 129,

Hope this helps! :)

7 0

3 years ago

Helpp plzz will mark brainleast

vladimir1956 [14]

Answer:

can we see the text and part a

like you know the question is asking abt that

4 0

3 years ago

If the factors of function f are (x - 6) and (x - 1), what are the zeros of function f?

lidiya [134]

X=6 and x=1

You can find your zeros by determining what you have to plug into the function in order for it to equal zero

If we plug in 6, for example we’d get (6-6)(x-1)

Simplified this is 0(x-1)

Anything times 0 is 0, so this is one of our zeros.

Same goes for x-1, we just need to plug in 1 for it to equal 0

Therefore there are zeros at x=1 and x=6 :))

7 0

3 years ago

You are planning a skating party at a rink that charges a basic fee of $6.00 and $6.50 per person for catered parties. You don’t

Alekssandra [29.7K]

Answer:

y = 6.50x + 6 or 71 = 6.50x + 6

10 people are the max you can invite

Step-by-step explanation:

We have the simple equation

y = 6.50x + 6

6.50x because it it per person

6 because it is a flat one time charge

We want the max to be 71 so that will be our y

71 = 6.50x + 6

We are now going to solve for x

65 = 6.5x

x = 10

Hope it helps! (:

4 0

3 years ago