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3 years ago

Using dimensional analysis convert 238.0 cm3 to L

Chemistry

1 answer:

Bezzdna [24]3 years ago

7 0

Answer:

= 0.238 L

Explanation:

From the given information:

To convert cm³ to L(liter), we utilize the advent of a unit fraction that comprises a liter in the upper part of the fraction(numerator) and a cubic centimeter in the lower part of the fraction(denominator)

Recall that:

1000 cm³ = 1 liter

∴

238.0 cm³ = $\dfrac{238.0 \ cm^3}{1} \times \dfrac{1 \ L}{1000 \ cm^3}$

= 0.238 L

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At a certain temperature, the K p Kp for the decomposition of H 2 S H2S is 0.834 . 0.834. H 2 S ( g ) − ⇀ ↽ − H 2 ( g ) + S ( g

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Answer:

Total pressure at equilibrium is 0.2798atm.

Explanation:

For the reaction:

H₂S(g) ⇄ H₂(g) + S(g)

Kp is defined as:

$Kp = \frac{P_{H_{2}}*P_S}{P_{H_{2}S}} = 0.834$

If initial pressure of H₂S is 0.150 atm, equilibrium pressures are:

H₂S(g): 0.150atm - x

H₂(g): x

S(g): x

Replacing in Kp:

$\frac{X*X}{0.150atm-X} = 0.834$

X² = 0.1251 - 0.834X

X² + 0.834X - 0.1251 = 0

Solving for X:

X = -0.964 → False solution: There is no negative pressures

X = 0.1298

Thus, pressures are:

H₂S(g): 0.150atm - 0.1298atm = 0.0202atm

H₂(g): 0.1298atm

S(g): 0.1298atm

Thus, total pressure in the container at equilibrium is:

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5 0

3 years ago

Read 2 more answers

How many moles of aqueous potassium ions and sulfate ions are formed when 63.7 g of K2SO4 dissolves in water

Viefleur [7K]

Answer:

WHEN 63.7 g OF K2SO4 IS DISSOLVED IN WATER, 0.73 MOLES OF POTASSIUM ION AND 0.366 MOLES OF SULFATE ION ARE FORMED.

Explanation:

Equation for the reaction:

K2SO4 + H20 ------->2 K+ + SO4^2-

When K2SO4 dissolves in water, potassium ion and sulfate ion are formed.

1 mole of K2SO4 produces 2 moles and 1 mole of SO4^2-

At STP, 1 mole of K2SO4 will be the molar mass of the substance

Molar mass of K2SO4 = ( 39 *2 + 32 + 16*4) g/mol

Molar mass = 174 g/mol

So therefore;

1 mole of K2SO4 contains 174 g and it produces 2 moles of potassium and 1 mole of sulfate ion

When 63.7 g is used; we have:

174 g = 2 moles of K+

63.7 g = ( 63.7 * 2 / 174) moles of K+

= 0.73 moles of K+

Forr sulfate ion, we have:

174 g = 1 mole ofSO4^2-

63.7 g = (63.7 * 1 / 174) moles of SO4^2-

= 0.366 moles of SO4^2-

In other words, when 63.7 g of K2SO4 is dissolved in water, 0.73 moles of potassium ion and 0.366 moles of sulfate ion are formed.

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Answer: A loss of the ion concentration gradient that drives this process.

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Water. Sound travels four times faster in water than it does in air.

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