Answer:
The molecular weight is 77.7 kg/mol
Explanation:
The molecular mass of hemoglobin is equal to:
Where
R = molar gas constant = 8.315 J/K mol
p = density = 0.998 g/mL
V = specific volume = 0.755 mL/g
s = sedimentation rate = ?
D = diffusion rate = 7x10⁻¹¹m²/s
T = temperature = 303 K
The sedimentation rate is equal to:
Where
w = angular velocity = 39300 rpm = 246929.18 rad/min
xb,30 = boundary midpoint distance at 30 min = 4.525 + 0.074 cm
t = time = 30 min
xb,0 = boundary midpoint distante at 0 min = 4.525 cm
The molecular weight is:
Answer: They are arranged by atomic number.
Answer:
- <em>As the temperature of a sample of matter is increased, the average kinetic energy of the particles in the sample </em><u>increase</u><em>.</em>
Explanation:
The <em>temperature</em> of a substance is the measure of the <em>average kinetic energy </em>of its partilces.
The temperature, i.e. how hot or cold is a substance, is the result of the collisions of the particles (atoms or molecules) of matter.
The kinetic theory of gases states that, if the temperature is the same, the average kinetic energy of any gas is the same, regardless the gas and other conditions.
This equation expresses it:
Where Avg KE is the average kinetic energy, R is the universal constant of gases, N is Avogadro's constnat, and T is the temperature measure in absolute scale (Kelvin).
As you see, in that equation Avg KE is propotional to T, which means that as the temperature is increased, the average kinetic energy increases.
"The other halogens are not as electronegative and so other hydrogen halides cannot form hydrogen bonds between molecules. Only London Forces are formed. - Therefore more energy is required to break the intermolecular forces in HF than the other hydrogen halides and so it has a higher boiling point."
not a hack link, just stating where i got your answer from! -
https://www.mytutor.co.uk/answers/17558/A-Level/Chemistry/Explain-the-unusually-high-boiling-point-of-HF/
<span>C. compounds that have the same atoms arranged in the same order, but with different three-dimensional orientations.</span>
