Question

How many moles of no2 are equivalent to 74.3g of no2

Answer 1

Answer;

= 1.615 moles

Explanation;

The molar mass of NO2

 = 46.01 g/mol

The mass of NO2 given is 74.3 g

Number moles = mass/ molar mass

                        = 74.3 g/ 46.01 g/mol

                       = 1.615 moles

Answer 2

Answer: The number of moles of $NO_2$ in 74.3 g of $NO_2$ is 1.62 moles.

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

Given :

Mass of $NO_2$= 74.3 g

Molar mass of $NO_2$ = 46 g/mol

Putting in the values, we get:

$\text{Number of moles of}NO_2=\frac{74.3g}{46g/mol}=1.62moles$

Thus the number of moles of $NO_2$ in 74.3 g of $NO_2$ is 1.62 moles.