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3 years ago

How many moles of no2 are equivalent to 74.3g of no2

Chemistry

2 answers:

AfilCa [17]3 years ago

6 0

<h3>Answer;</h3>

= 1.615 moles

<h3>Explanation;</h3>

The molar mass of NO2

= 46.01 g/mol

The mass of NO2 given is 74.3 g

Number moles = mass/ molar mass

= 74.3 g/ 46.01 g/mol

= 1.615 moles

DerKrebs [107]3 years ago

4 0

Answer: The number of moles of $NO_2$ in 74.3 g of $NO_2$ is 1.62 moles.

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

Given :

Mass of $NO_2$ = 74.3 g

Molar mass of $NO_2$ = 46 g/mol

Putting in the values, we get:

$\text{Number of moles of}NO_2=\frac{74.3g}{46g/mol}=1.62moles$

Thus the number of moles of $NO_2$ in 74.3 g of $NO_2$ is 1.62 moles.

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Answer:

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Answers to statement 1 , 2,5 and 8

Answers to statement 1 , 2

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From liquid to solid and gas to liquid

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In Both for water and other substance

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Answers to statement 5,8 :

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This can be explained using the phase diagram of water :

The line DB is = the solid-liquid coexistence line

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4. the solid-liquid coexistence line has a negative slope.

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Answer:

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