Answer:
∠AOC
Step-by-step explanation:
The statement "A to O to C" is talking about each of the points that form an angle. Each point is given a letter as its name.
The symbol ∠ <u>means angle</u>.
You need two lines to form an angle, and you need two points to form a line. By reusing one of the points, you need three points to form an angle. The point that is being reused is always the point in the middle, in this case, that point is called 'O'.
P(subject
lied | negative results) = 4/19
P(negative
results | subject lied) = 8/49
I am hoping that these answers
have satisfied your queries and it will be able to help you in your endeavors, and
if you would like, feel free to ask another question.
The tuition would be $6143.94 next year
<h3>How to detemrine the tuition amount?</h3>
The given parameters are:
- Current amount = $5,742
- Rate of increment, r = 7%
The tuition next year is then calculated as:
Tuition = Current * (1 + Rate)
This gives
Tuition = $5,742 * (1 + 7%)
Evaluate
Tuition = $6143.94
Hence, the tuition would be $6143.94 next year
Read more about rates at:
brainly.com/question/25545513
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Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)