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yKpoI14uk [10]
2 years ago
7

3. Which of the following is not true for atoms? (4 points) They combine to form elements and molecules. They contain negatively

charged electrons. They are the building blocks of matter. They are made up of elements.
Chemistry
1 answer:
Taya2010 [7]2 years ago
7 0
<h3><u>Answer;</u></h3>

They are made up of elements.

<h3><u>Explanation;</u></h3>
  • An atom is the smallest particle of matter that still retains the property of the element.
  • Two or more atoms combine to form elements or compounds. Elements are formed by two or more similar atoms, while compounds are formed by two or more different elements.
  • Atoms are made up of subatomic particles; protons, electrons and neutrons. Electrons are negatively charged, protons are positively charged while neutrons have no charge.
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7. A student has a 25 g sample of gas in a container at STP and adds another 7
BigorU [14]

Answer:

New temperature t2 = [1.28T− 273.15]° C

Explanation:

Given:

Volume v1 = 25 gram

New volume v2 = 25 + 7 = 32 gram

Constant pressure = p

Temperature t1 = T

Find:

New temperature t2

Computation:

Pv1/t1 = Pv2/t2

25 / T = 32 / t2

t2 = 1.28T

New temperature t2 = [1.28T− 273.15]° C

4 0
2 years ago
How many grams of Cu(OH)2 will precipitate when excess NaOH solution is added to 46.0 mL of 0.584 M CuSO4
Slav-nsk [51]
<h3>Answer:</h3>

2.624 g

<h3>Explanation:</h3>

The equation for the reaction is given as;

  • CuSO₄(aq) + 2NaOH(aq) → Cu(OH)₂(s) + Na₂SO₄(aq)
  • Volume of CuSO₄ as 46.0 mL;
  • Molarity of CuSO₄ as 0.584 M

We are required to calculate the mass of Cu(OH)₂ precipitated

  • We are going to use the following steps;
<h3>Step 1: Calculate the number of moles of CuSO₄ used</h3>

Molarity = Number of moles ÷ Volume

To get the number of moles;

Moles = Molarity × volume

          = 0.584 M × 0.046 L

          = 0.0269 moles

<h3>Step 2: Calculate the number of moles of Cu(OH)₂ produced </h3>
  • From the equation 1 mole of CuSO₄ reacts to give out 1 mole of Cu(OH)₂
  • Therefore; Mole ratio of CuSO₄ to Cu(OH)₂ is 1 : 1.

Thus, Moles of CuSO₄ = Moles of Cu(OH)₂

Hence, moles of Cu(OH)₂ = 0.0269 moles

<h3>Step 3: Calculate the mass of Cu(OH)₂</h3>

To get mass we multiply the number of moles with the molar mass.

Mass = Moles × Molar mass

Molar mass of Cu(OH)₂ is 97.561 g/mol

Therefore;

Mass of Cu(OH)₂ = 0.0269 moles × 97.561 g/mol

                           = 2.624 g

Thus, the mass of Cu(OH)₂ that will precipitate is 2.624 g

3 0
3 years ago
You bought a new car and estimated that your monthly payment would be $312. However, your actual payment amount was $325. How mu
Romashka-Z-Leto [24]

Answer:

The error would be $13.

Explanation:

Given data:

Actual payment = $325

estimated payment = $312

Error = ?

Solution:

Error =  Estimated payment - Actual payment

Error = $312  -  $325

Error = -$13

we can discard the negative sign and consider the absolute value. The error would be $13.

5 0
3 years ago
If you place rice on top or a speaker, what will happen to the rice when you turn the speaker on?
Dovator [93]

Answer:

The rice will move

Explanation:

the sound vibration and waves will cause the rice to move

3 0
2 years ago
A gas mixture contains 10.0 mole% H2O (v) and 90.0 mole % N2. The gas temperature and absolute pressure at the start of each of
Rainbow [258]

Answer: (a). T = 38.2 °C     (b). V = 1.3392 cm³     (c). ii and iii  

Explanation:

this is quite easy to solve, i will give a step by step analysis to solving this problem.

(a). from the question we have that;

the Mole fraction of Nitrogen, yи₂ = 0.1

Also the Mole fraction of Water, yн₂o = 0.1

We know that the vapor pressure is equal to the partial pressure because the vapor tends to condense at due point.

ρн₂o = ṗн₂o

      = yн₂oP = 0.1 × 500 mmHg = 50 mmHg

from using Antoine equation, we apply the equation

logρн₂o = A - B/C+T

T = B/(A - logρн₂o) - C

  = 1730.63 / (8.07131 - log 50mmHg) - 223.426

T = 38.2 °C

We have that the temperature for the first drop of liquid form is 38.2 °C

(b). We have to calculate the total moles of gas mixture in a 30 litre flask;

   n  = PV/RT  

   n = [500(mmHG) × 30L] / [62.36(mmHGL/mol K) × 323.15K] = 0.744 mol

Moles of H₂O(v) is 0.1(0.744) = 0.0744 mol

Moles of N₂ is 0.9(0.744) = 0.6696 mol

we have that the moles of water condensed is 0.0744 mol i.e the water vapor  in the flask is condensed

Vн₂o = 0.0744 × 18 / 1 (g/cm³)

Vн₂o = 1.3392 cm³

Therefore, the  volume of the liquid water is 1.3392 cm³

(3). (ii) and (iii)

The absolute pressure of the gas and The partial pressure of water in the gas would change if the barometric pressure drops.

cheers i hope this helps!!!!

4 0
3 years ago
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