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2 years ago

What question could be asked to help determine whether the solar system is heliocentric or geocentric?

Chemistry

1 answer:

Alex_Xolod [135]2 years ago

3 0

C because of the planets that Chablé and focus of them

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What is the average atomic mass of hafnium given the following abundance information on the isotopes?

Goryan [66]

Answer:

178.55

Explanation:

176 × 0.05+ 177 × 0.19 + 178 × 0.27 + 179 × 0.14 + 180 × 0.35 = 178.55

7 0

2 years ago

8. Rewrite each of the following as an "ordinary” decimal

saveliy_v [14]

Answer:

????????

Explanation:

3 0

3 years ago

Which element is found in all the acids described in this section?

mixer [17]

Acids contain hydrogen!

8 0

2 years ago

An increase in temperature affects the reaction rate by >decreasing the velocities of particles that collide in the reaction.

Bond [772]

Answer:

increasing the number of molecules that have sufficient kinetic energy to react.

Explanation:

An increase in temperature affects the reaction rate by increasing the number of molecules that have sufficient kinetic energy to react.

or we say; temperature increase, leads to an increase in the amount of collisions between molecules.

4 0

3 years ago

Read 2 more answers

g Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produc

Gala2k [10]

$\text{Ammonia has been studied as an alternative "clean" fuel for internal combustion}$

$\text{engines, since its reaction with oxygen produces only nitrogen and water vapor,}$

$\text{and in the liquid form it is easily transported. An industrial chemist studying this}$

$\text{reaction fills a} \ \mathbf{100 \ L }\ \text{tank with} \ \mathbf{8.6 \ mol} \ \text{of ammonia gas and} \ \mathbf{28 \ mol} \ \ \text{of oxygen gas, }$

$\text{to be} \ \mathbf{2.6\ mol} \ .\ \text{Calculate the concentration equilibrium constant for the combustion of}$

$\text{ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.}$

Answer:

Explanation:

From the correct question above:

The reaction can be represented as:

$\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }$

From the above reaction; the ICE table can be represented as:

$\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }$

I (mol/L) 0.086 0.28 0 0

C -4x -3x +2x +6x

E 0.086 - 4x 0.28 - 3x +2x +6x

At equilibrium;

The water vapor = $\dfrac{2.6 \ mol}{100 \ L} = 6x$

$x = \dfrac{2.6}{100} \times \dfrac{1}{6}$

$x = 0.00433$

$\text{equilibrium constant} ({k_c}) = \dfrac{ [N_2]^2 [H_2O]^6 }{ [[NH_3]^4] [O_2]^3 }$

$\implies \dfrac{(2x)^2 (6x)^6}{(0.086-4x)^4\times (0.28-3x)^3} \\ \\$

Replacing the value of x, we have:

$K_c = \dfrac{4 \times 46,656 \times x^8}{(0.086-4x)^4\times (0.28 -3x)^3} \\ \\ K_c = \dfrac{4 \times 46656 \times (0.00433)^8}{(0.06868)^4(0.26701)^3} \\ \\ K_c = \mathbf{5.4446 \times 10^{-8}}$

$K_c = \mathbf{5.5 \times 10^{-8} \ to \ 2 \ significant \ figures}$

5 0

3 years ago