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marusya05 [52]
3 years ago
7

How much heat is needed to boil 3,000 mL of water at its boiling point, 100 C?

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer: 100C of heat is needed.

Explanation: That is the heating point of water

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using the symbol M for the element, write the chemical formula for the compound that forms when element M reacts with iodine.
Anon25 [30]

Answer : The chemical formula for the compound is, MI

Explanation :

When the element 'M' react with the I_2 to give MI.

The balanced chemical reaction is,

2M+I_2\rightarrow 2MI

In this reaction, 'M' is in mono-atomic form and I_2 is in diatomic form.

By the stoichiometry,

2 moles 'M' react with the 1 mole of I_2 to give 2 moles of MI.

Therefore, the chemical formula of the compound is, MI


6 0
3 years ago
Read 2 more answers
Como se representan los elementos en la tabla¿?
Shalnov [3]

Answer:

Na sodiops los elementos químicos se representan como el átomo, el núcleo, donde se necuentran los protones y neutrones van dentro, los electrones afuera, girando de forma elíptica alrededor del núcleo. ... por ejemplo el oxígeno numero atómico 8, tiene 8 protones y 8 electrones. el número de neutrones es diferente.

Explanation:

4 0
2 years ago
A little boy has placed his pet squirrel into a balloon with a volume of 3L at a pressure of 1.0 atm. If the boy takes his pet s
s2008m [1.1K]

Answer: The squirrel's balloon will be 0.86 L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=1.0atm\\V_1=3L\\P_2=3.5atm\\V_2=?

Putting values in above equation, we get:

1.0\times 3L=3.5\times V_2\\\\V_2=0.86

Thus the squirrel's balloon will be 0.86 L

7 0
3 years ago
A monoprotic weak acid when dissolved in water is 0.66% dissociated and produces a solution with a pH of 3.04. Calculate the Ka
raketka [301]

Answer:

Ka = 6.02x10⁻⁶

Explanation:

The equilibrium that takes place is:

  • HA ⇄ H⁺ + A⁻
  • Ka = [H⁺][A⁻]/[HA]

We <u>calculate [H⁺] from the pH</u>:

  • pH = -log[H⁺]
  • [H⁺] = 10^{-pH}
  • [H⁺] = 9.12x10⁻⁴ M

Keep in mind that [H⁺]=[A⁻].

As for [HA], we know the acid is 0.66% dissociated, in other words:

  • [HA] * 0.66/100 = [H⁺]

We <u>calculate [HA]</u>:

  • [HA] = 0.138 M

Finally we <u>calculate the Ka</u>:

  • Ka = \frac{[9.12x10^{-4}]*[9.12x10^{-4}]}{[0.138]} = 6.02x10⁻⁶
3 0
2 years ago
Consider the formation of hcn by the reaction of nacn (sodium cyanide) with an acid such as h2so4 (sulfuric acid): 2nacn(s)+h2so
Artemon [7]

2NaCN(s) + H₂SO₄(aq) --> Na₂SO₄(aq) + 2HCN(g)  

The molar ratio between NaCN : HCN is 2:2  or 1:1

Mass of HCN = 16.7 g

Molar mass of HCN = 1 + 12 + 14 = 27 g/mol

Molar mass of NaCN = 49 g/mol

Therefore, the mass of NaCN is

16.7 g of  HCN x 49 g/mol of NaCN / 27 g/mol of HCN = 30.3 grams of NaCN

Therefore, 30.3 grams of NaCN gives the lethal dose in the room.

5 0
3 years ago
Read 2 more answers
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