Answer:
Bi (Bismuth)
Ag (Silver)
Li (Lithium)
Explanation:
Xe (Xenon) and I (Iodine) are non-metals. They cannot from a metallic bond because metallic bonds are bonds between metals only.
Answer: Use the titration formula
Explanation:
Moles of X are 0.925 moles.
A mole is a totally vital unit of dimension that chemists use.The mole, symbol mol, is the unit of amount of substance inside the worldwide device of gadgets. the amount quantity of the substance is a measure of how many simple entities of a given substance are in an item or sample. The mole is described as containing exactly 6.02214076×10²³ primary entities
mass of X2O3 = 4 g
so moles = mass/molar mass
molar mass of X2O3 = 2*X + 48 -
Given, that the mass of X = 2.8g
mass of O = 4 - 2.8 = 1.2g
A mole of O = 1.2g/16 = 0.075 mole
∴ mole of X = 1 - 0.075 = 0.925 moles.
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Answer:
The answer is "10.84 g".
Explanation:
The formula for calculating the number for moles:
In the given acid nitric:
Owing to the nitric acid mass = 
Nitric acid molar weight
If they put values above the formula, they receive:
In the given chemical equation:
In this reaction, 2 mols of nitric acid are produced by 1 mole of water.
So, 1.204 moles of nitric acid will be produced:
We are now using Equation 1 in determining the quantity of water:
Water moles 
Water weight molar 
Answer:
Keqq = 310
Note: Some parts of the question were missing. The missing values are used in the explanation below.
Explanation:
<em>Given values: ΔH° = -178.8 kJ/mol = -178800 J/mol; T = 25°C = 298.15 K; ΔS° = -552 J/mol.K; R = 8.3145 J/mol.K</em>
Using the formula ΔG° = -RT㏑Keq
㏑Keq = ΔG°/(-RT)
where ΔG° = ΔH° - TΔS°
㏑Keq = ΔH° - TΔS°/(-RT)
㏑Keq = {-178800 - (-552 * 298.15)} / -(8.3145 * 298.15)
㏑Keq = -14221.2/-2478.968175
㏑Keq = 5.73674166
Keq = e⁵°⁷³⁶⁷⁴¹⁶⁶
Keq = 310.05
