Answer:
Applied voltage should be 13.5396 kV
Explanation:
The charge stored by a capacitor when subjected to a potential difference 'v' across it's plates is given by
![Q=\frac{K\epsilon _{o} A}{d}V](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7BK%5Cepsilon%20_%7Bo%7D%20A%7D%7Bd%7DV)
Solving for V we get
![V=\frac{Qd}{K\epsilon _{o}A}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BQd%7D%7BK%5Cepsilon%20_%7Bo%7DA%7D)
thus to store a charge of 0.11mC we solve for V as follows
Applying values we get
![V=\frac{0.11\times 10^{-3}\times 0.01\times 10^{-3}}{27\times 10^{-4}\times 3.4\times 8.85\times 10^{-12}}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B0.11%5Ctimes%2010%5E%7B-3%7D%5Ctimes%200.01%5Ctimes%2010%5E%7B-3%7D%7D%7B27%5Ctimes%2010%5E%7B-4%7D%5Ctimes%203.4%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%7D)
![\therefore V=13.5396kV](https://tex.z-dn.net/?f=%5Ctherefore%20V%3D13.5396kV)
Answer:
Un medidor de fuerza
A force gauge for all you English speakers
Explanation:
Un medidor de fuerza es un instrumento de medición que se utiliza para medir fuerzas.
A force gauge is a measuring instrument used to measure forces.
Scientific law...is a phenomenon of nature that has been proven to invariably occur whenever a certain conditions exist
Answer:
v = 2 m/s
Explanation:
Here we can use energy conservation to find the speed at the lowest point on its trajectory
As we know that by energy conservation
initial total gravitational potential energy = final total kinetic energy
now the height that is moved by the pendulum while it swing down is given as
![h = L(1 - cos30)](https://tex.z-dn.net/?f=h%20%3D%20L%281%20-%20cos30%29)
![h = 1.5(1 - cos30) = 0.200 m](https://tex.z-dn.net/?f=h%20%3D%201.5%281%20-%20cos30%29%20%3D%200.200%20m)
now we can use energy conservation as
![mgh = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=mgh%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![v = \sqrt{2gh}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2gh%7D)
![v = \sqrt{2(9.8)(0.200)}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2%289.8%29%280.200%29%7D)
![v = 2 m/s](https://tex.z-dn.net/?f=v%20%3D%202%20m%2Fs)