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never [62]
2 years ago
13

Which is the correct answer?

Physics
1 answer:
Masja [62]2 years ago
3 0
The correct answer is A, 2x^3 - x^2 +3x +7

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A record player turntable initially rotating at 3313 rev/min is braked to a stop at a constant rotational acceleration. The turn
Rus_ich [418]

Answer:

(A) It will take 22 sec to come in rest

(b) Work done for coming in rest will be 0.2131 J              

Explanation:

We have given the player turntable initially rotating at speed of 33\frac{1}{3}rpm=33.333rpm=\frac{2\times 3.14\times 33.333}{60}=3.49rad/sec

Now speed is reduced by 75 %

So final speed \frac{3.49\times 75}{100}=2.6175rad/sec

Time t = 5.5 sec

From first equation of motion we know that '

\alpha =\frac{\omega -\omega _0}{t}=\frac{2.6175-3.49}{4}=-0.158rad/sec^2

(a) Now final velocity \omega =0rad/sec

So time t to come in rest  t=\frac{0-3.49}{-0.158}=22sec

(b) The work done in coming rest is given by

\frac{1}{2}I\left ( \omega ^2-\omega _0^2 \right )=\frac{1}{2}\times 0.035\times (0^2-3.49^2)=0.2131J

4 0
2 years ago
Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 53 km/h. After six hour
Serhud [2]
For the answer to the question above, first find out the gradient. 

<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>

<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>

<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>

<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>

<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
4 0
3 years ago
Newton's Law of Gravitation states that two bodies with masses m1 and m2 attract each other with a force F, where r is the dista
Marrrta [24]

Answer:

W = - 5.01 10¹⁰ J

Explanation:

Work is defined by the expression

      W = ∫ F.dr

Where the blacks indicate vectors, in the case the force is radial and the distance is also radial, whereby the scalar producer is reduced to an ordinary product

      W = ∫ F dr

      W = G m₁m₂ ∫ 1 /r² dr

     W = G m₁ m₂2(-1 / r)

We evaluate between the lower limits r = Re and upper r = ∞

     W = G m₁m₂ (-1 / Re + 1 / ∞)

     W = - G m₁ m₂ / Re

Let's calculate

    W = - 6.67 10⁻¹¹ 800 5.98 10²⁴ / 6.37 10⁶

    W = - 5.01 10¹⁰ J

4 0
3 years ago
Study this image. Which statement correctly explains what is happening in the image?
klemol [59]

Answer:

A rift valley is forming.

Explanation:

A rift valley is a linear shaped lowland between several highlands or mountain ranges created by the action of a geologic rift or fault.

A rift valley is formed on a divergent plate boundary, a crustal extension or spreading apart of the surface.

The arrows show the movement of the tectonic plates.

Hope this helps.

-Gumina

8 0
3 years ago
The maximum stress in a section of a circular tube subject to a torque is τmax = 27 MPa . If the inner diameter is Di = 3.75 cm
DIA [1.3K]

Answer:

T_{max} = 4.735\,kN\cdot m

Explanation:

The shear stress due to torque can be calculed by using the following model:

\tau_{max} = \frac{T_{max}\cdot r_{ext}}{J_{tube}}

The maximum torque on the section is:

T_{max} = \frac{\tau_{max}\cdot J_{tube}}{r_{ext}}

The Torsion Constant for the circular tube is:

J_{tube} = \frac{\pi}{32}\cdot (D_{ext}^{4}-D_{int}^{4})

J_{tube} = \frac{\pi}{4}\cdot [(0.053\,m)^{4}-(0.038\,m)^{4}]

J_{tube} = 4.560\times 10^{-6}\,m^{4}

Now, the require output is computed:

T_{max} = \frac{(27\times 10^{3}\,kPa)\cdot (4.560\times 10^{-6}\,m^{4})}{0.026\,m}

T_{max} = 4.735\,kN\cdot m

7 0
3 years ago
Read 2 more answers
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