Answer:
(A) It will take 22 sec to come in rest
(b) Work done for coming in rest will be 0.2131 J
Explanation:
We have given the player turntable initially rotating at speed of 
Now speed is reduced by 75 %
So final speed 
Time t = 5.5 sec
From first equation of motion we know that '
(a) Now final velocity 
So time t to come in rest 
(b) The work done in coming rest is given by
For the answer to the question above, first find out the gradient.
<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>
<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>
<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>
<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>
<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
Answer:
W = - 5.01 10¹⁰ J
Explanation:
Work is defined by the expression
W = ∫ F.dr
Where the blacks indicate vectors, in the case the force is radial and the distance is also radial, whereby the scalar producer is reduced to an ordinary product
W = ∫ F dr
W = G m₁m₂ ∫ 1 /r² dr
W = G m₁ m₂2(-1 / r)
We evaluate between the lower limits r = Re and upper r = ∞
W = G m₁m₂ (-1 / Re + 1 / ∞)
W = - G m₁ m₂ / Re
Let's calculate
W = - 6.67 10⁻¹¹ 800 5.98 10²⁴ / 6.37 10⁶
W = - 5.01 10¹⁰ J
Answer:
A rift valley is forming.
Explanation:
A rift valley is a linear shaped lowland between several highlands or mountain ranges created by the action of a geologic rift or fault.
A rift valley is formed on a divergent plate boundary, a crustal extension or spreading apart of the surface.
The arrows show the movement of the tectonic plates.
Hope this helps.
-Gumina
Answer:
Explanation:
The shear stress due to torque can be calculed by using the following model:
The maximum torque on the section is:
The Torsion Constant for the circular tube is:
![J_{tube} = \frac{\pi}{4}\cdot [(0.053\,m)^{4}-(0.038\,m)^{4}]](https://tex.z-dn.net/?f=J_%7Btube%7D%20%3D%20%5Cfrac%7B%5Cpi%7D%7B4%7D%5Ccdot%20%5B%280.053%5C%2Cm%29%5E%7B4%7D-%280.038%5C%2Cm%29%5E%7B4%7D%5D)
Now, the require output is computed:
