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Degger [83]
2 years ago
9

What are two ways you can increase power by climbing the stairs?

Physics
1 answer:
Nina [5.8K]2 years ago
8 0

Answer:

change the

  • time
  • distance
  • force.

Explanation:

P = W/time

W = F*d

You have control over how fast you go up the stairs.

You also have control over how far up the stairs you go.

Therefore the answer is

  • time
  • distance

If you don't like distance as an answer, you can carry something up the stairs -- anything that increases F will do.

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What is center of mass?
yuradex [85]
“a point representing the mean position of the matter in a body or system.”
3 0
3 years ago
Waves begin to "feel bottom" when the depth of water is
LekaFEV [45]
I think the correct answer would be one half the wavelength. Waves would "feel bottom" when the water is at the depth of 0.5 of the wavelength. "Feel bottom" is a term used to describe that the depth of water affects the wave properties. Hope this answers the question.
8 0
2 years ago
Read 2 more answers
Charge q is accelerated starting from rest up to speed v through the potential difference V. What speed will charge q have after
adoni [48]

Answer: v = 1.19 * 10^{6} m/s

Explanation: q = magnitude of electronic charge = 1.609 * 10^{-19} c

mass of an electronic charge = 9.10 * 10^{-31} kg

V= potential difference = 4V

v = velocity of electron

by using the work- energy theorem which states that the kinetic energy of the the electron must equal the work done use in accelerating the electron.

kinetic energy = \frac{mv^{2} }{2},  potential energy = qV

hence, \frac{mv^{2} }{2} = qV

\frac{9.10 *10^{-31} * v^{2}  }{2} = 1.609 * 10^{-16} * 4\\\\\\\\9.10*10^{-31}  * v^{2} = 2 * 1.609 *10^{-16} * 4\\\\\\9.10 *10^{-31} * v^{2} = 1.287 *10^{-15} \\\\v^{2} = \frac{1.287 *10^{-15} }{9.10 *10^{31} } \\\\v^{2} = 1.414*10^{15} \\\\v = \sqrt{1.414*10^{15} } \\\\v = 1.19 * 10^{6} m/s

7 0
2 years ago
Sandy is whirling a ball attached to a string in a horizontal circle over his head. If Sandy doubles the speed of the ball, what
jeka57 [31]

The tension in the string B) It quadruples.

Explanation:

The ball is in uniform circular motion in a horizontal circle, so the tension in the string is providing the centripetal force that keeps the ball in circular motion. So we can write:

T= m\frac{v^2}{r}

where:

T is the tension in the string

m is the mass of the ball

v is the speed of the ball

r is the radius of the circle (the lenght of the string)

In this problem, we are told that the speed of the ball is doubled, so

v' = 2v

Substituting into the previous equation, we find the new tension in the string:

T' = m \frac{(2v)^2}{r}=4(m\frac{v^2}{r})=4T

Therefore, the tension in the string will quadruple.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

6 0
3 years ago
a bicycle travels at a velocity of -2.33 m/s and has a displacement of -58.3 m. how much time did it take?
Alexandra [31]
We know that velocity is equal to the total displacement of an object over time.
velocity =  \frac{displacement}{time}
Deriving from that equation, we can say that:
t =  \frac{d}{v}
Okay, so here it goes:
t =  \frac{58.3m}{2.33 \frac{m}{s} } \\ t = 25.02s
The bicycle took 25.02 seconds to displace at 58.3 meters.
5 0
3 years ago
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