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3 years ago

What are two ways you can increase power by climbing the stairs?

Physics

1 answer:

Nina [5.8K]3 years ago

8 0

Answer:

change the

time
distance
force.

Explanation:

P = W/time

W = F*d

You have control over how fast you go up the stairs.

You also have control over how far up the stairs you go.

Therefore the answer is

time
distance

If you don't like distance as an answer, you can carry something up the stairs -- anything that increases F will do.

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What are the dimensions of a frequency in physics

Burka [1]

Answer:

This is the information I can provide. I hope it helps

Explanation:

Frequency is measured in units of hertz (Hz) which is equal to one occurrence of a repeating event per second. The period is the duration of time of one cycle in a repeating event, so the period is the reciprocal of the frequency.

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4 years ago

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(BRAINLIEST)<br><br> Question: Name 2 waves that you use in your everyday life.

Archy [21]

-- Radio waves. (To hear the weather while I'm waking up.)

-- Light waves. (To see where the dog is so I don't step on him.)

-- Infrared waves. (To make my toast for breakfast.)

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4 years ago

A laser beam from Earth is reflected by a mirror placed on the Moon. If the speed of the beam is 3.00 x 108 m / s and the distan

Olin [163]

Answer:

1.27seconds

Explanation:

Speed = 324 m/s , Distance = 411.48m

Time = Distance/Speed

Time = 411.48/324 seconds

Time = 1.27seconds ( Ans)

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3 years ago

A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of

Dominik [7]

Answer:

The centripetal acceleration of the runner as he runs the curved portion of the track is 0.91 m/s²

Explanation:

Given;

distance traveled in the given time = 200 m

time to cover the distance, t = 29.6 s

speed of the runner, v = d / t

v = 200 / 29.6

v = 6.757 m/s

The centripetal acceleration of the runner is given by;

$a_c = \frac{V^2}{r}$

where;

r is the radius of the circular arc, given as 50 m

Substitute the givens;

$a_c = \frac{V^2}{r}\\\\a_c = \frac{(6.757)^2}{50}\\\\a_c = 0.91 \ m/s^2$

Therefore, the centripetal acceleration of the runner as he runs the curved portion of the track is 0.91 m/s².

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3 years ago

The table lists pressure and volume values for a particular gas. Which is the best estimate for the value of V at P = 7.0 × 103

Tju [1.3M]

Answer:

2.0 × 104 2.0

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3 years ago