All categories

4 years ago

How was the water filtered to remove debris and living organisms?

2 answers:

5 0

The most common method in removing debris and living organisms is through a series of sedimentation and heat application. The role of sedimentation is to use gravity in separating drinkable water and visible debris. While treating water with heat kills the living organisms.

astra-53 [7]4 years ago

4 0

Step-1: Coagulation

Coagulation removes fine particles suspended in water, after removing rough debris by filtering through the screen.
Alum and other chemicals are added to water to form small sticky particles called floc, which attracts suspended particles.
The combined weight of these particles and alum (floc) becomes heavy enough to sink.

Step-2: Sedimentation

Coagulated particles fall gravitationally through the water in a settling tank and accumulate at the bottom of the tank, cleaning water from much solid debris.

Step-3: Filtration

To remove solid particles that were previously unremoved by sedimentation, water from the sedimentation tank flows through:

sand,
gravel,
coal, and
activated charcoal.

Step-4: Disinfection

Disinfection methods are applied to filtered water to destroy hazardous microorganisms as living organisms.

A chlorine residue is added to water when leaving the processing plant to help protect treated water from recontamination when moving through the distribution system.

<h3>Further explanation</h3>

Chemical precipitation or coagulation with various aluminum salts (e.g., alum), iron, lime, and other organic or inorganic chemicals is widely used to treat water to remove colloidal particles (turbidness) and microbes.

Water treatment with the addition of coagulants and chemical deposits has been carried out since ancient times.

There are main things to know about the different terms of water purification and filtration because they are not synonyms.

Water filtration is a treatment for eliminating debris, and some bacteria as living organisms, through several types of filters like cloth or nets.
Water purification is a chemical or UV process (with heat treatment) to deactivate bacteria and other hazardous substances that are not functioning.

<h3>Learn more</h3>

The reason why water is a compound brainly.com/question/4636675
How many carbon atoms are there in a 1.3-carat diamond? brainly.com/question/4235993
Types of fatty acids brainly.com/question/1386856

Keywords: how was the water, filtered, to remove, debris and living organisms, microorganisms, bacteria, microbes, colloidal particles, coagulation, sedimentation, filtration, disinfection, purification

You might be interested in

A model rocket is shot directly upward, rises to its maximum height and then returns to its launch position in 10.0 s. Assuming

worty [1.4K]

d. 49.0 m/s

this is your answer. ....OK. ..

please mark me as brainliest. .....

follow me.....my friend. .....

3 0

3 years ago

Arsenic diffusion in Si: Arsenic is diffused into a thick slice of silicon with no previous arsenic in it at 1100ºC. If the surf

Rainbow [258]

Answer:

Diffusion time is 7.42 h

Solution:

As per the question:

Temperature, T = $1100^{\circ}C$

Surface concentration of arsenic, $C_{S} = 5.0\times 10^{18}\ atoms/cm^{3}$

Surface concentration below Silicon surface, $C_{x} = 1.5\times 10^{16}\ atoms/cm^{3}$

D = $3.0\times 10^{- 14}\ cm^{2}/s$

x = $1.2\mu m = 1.2\times 10^{- 4}\ cm$

Initial concentration at t = 0, $C_{o} = 0$

Now, by using Flick's second eqn:

$\frac{C_{S} - C_{x}}{C_{x} - C_{o}} = erf(\frac{x}{\sqrt{Dt}})$

Thus by putting appropriate values:

$\frac{5.0\times 10^{18} - 1.5\times 10^{16}}{5.0\times 10^{18}} = erf(\frac{1.2\times 10^{- 4}}{2\sqrt{3.0\times 10^{- 14}t}})$

$0.997 = erf(\frac{364.4}{\sqrt{t}})$ (1)

Now,

$erf(z) = 0.997$

Now, from error function values tabulation:

For z = 2.0, erf(z) = 0.998

For z = 2.2, erf(z) = 0.995

Now,

With the help of linear interpolation method:

$\frac{z - 2}{2.2 - 2.0} = \frac{0.997 - 0.995}{0.998 - 0.995}$

z = 2.12

Now, using eqn (1) and above value:

$\frac{364.4}{\sqrt{t}} = 2.12$

$t = (\frac{364.4}{2.12})^{2}$ = 26700 s

t = $\frac{26700}{3600} = 7.42\ h$

7 0

3 years ago

Select the correct answer

Nadya [2.5K]

Answer:

$f= 3.0 \times 10 {}^{8} \div 7.0 \times 10 {}^{7} \\ f = 4.28hz$

Given

7 0

3 years ago

Now assume that the frictional force f is not at its maximum value. What is the relation between the torque Ï„ applied to each w

leva [86]

Answer:

a)The direction the frictional force will acts is in the positive x direction.

Explanation:

a)The direction the frictional force will acts is in the positive x direction

b)in the horizontal direction, the total force F(total) is equal to 4times the frictional force in the wheel.

F(total)=4f

''f'' is taken as the frictional force.

c)4times the normal force on each wheel minus the acceleration equals zero i.e 4N(wheel)-a=0

=4N(wheel)-mg=0

d) torque is the force that tends to bend rotation

ζ=rf

but acceleration=4×frictional force

cross multiply

f=ζ/r

f=ma/4

ma/4=ζ/r

a=4ζ/r

5 0

4 years ago

Read 2 more answers

An ideal gas initially at 4.00atm and 350 K is permitted

Nuetrik [128]

Explanation:

It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is $P_{2}$ and final temperature is $T_{2}$ .