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Marina CMI [18]
2 years ago
10

Look at the diagram. Which of the following is another name 22? с. А D 1/2 B

Mathematics
1 answer:
stiks02 [169]2 years ago
6 0

Answer:

i think another name for angel 2 is CBD or DBC i ain't sure

Step-by-step explanation:

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Kesia knows that 1/4=0.25. Explain how she could use this fact to determine the decimal equivalent of 5/8
STatiana [176]
She knows that
0.25 =  \frac{1}{4}  =  \frac{2}{8}
\frac{5}{8}  =  \frac{2}{8}  +  \frac{2}{8}  +  \frac{1}{8}  = \\ 0.25 + 0.25 +  \frac{0.25}{2} =   \\ 0.25 + 0.25 + 0.125 = 0.625
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3 years ago
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What is the value of x?<br> A<br> 160°<br> 95"<br> A. 359<br> B. 60°<br> C. 155°<br> D. 250
Svetradugi [14.3K]

Answer:

The value of x is 25°.

Here is your solutions too.

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2 years ago
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ACD is a triangle and B is a point on AC. AB = 8cm and BC is 6cm. Angle BCD = 48° and angle BDC = 50°. (a) Find the length of BD
FromTheMoon [43]

Answer:

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  • 10.528 cm
  • 23.056 cm^2

Step-by-step explanation:

(a) The Law of Sines can be used to find BD.

  BD/sin(48°) = BD/sin(50°)

  BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm

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(b) We can use the Law of Cosines to find AD.

  AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°

  AD^2 ≈ 110.841

  AD ≈ √110.841 ≈ 10.5281 . . . cm

__

(c) The area of ∆ABD can be found using the formula ...

  A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°

  A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2

_____

Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.

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