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zzz [600]
3 years ago
11

Refrigerant-134a enters an adiabatic compressor as saturated vapor at 160 kPa at a rate of 2.4 m3/min and is compressed to a pre

ssure of 900 kPa. Determine the minimum power that must be supplied to the compressor. Use the tables for R-134a
Engineering
1 answer:
Alexeev081 [22]3 years ago
3 0

Answer:

<h2>11.65kW</h2>

Explanation:

Step one:

given data

from the table  for R-134a

<em>For the given pressure state the following data were extracted.</em>

s=0.94202kJ/kg.K

h1=241.14kJ/kg

∝1=0.12355m^3/kg

<em>By interpolation, the final enthalpy and pressure with data from the table of  R-134a</em>

<em>h2=277.12kJ/kg</em>

The minimum power output is then determined from the energy balance

W=m(h2-h1)

W=V1/∝1(h2-h1)

W=2.4/60/0.12355(277.12-241.14)

W=0.04/0.12355(35.98)

W=0.3237(35.98)

W=11.65kW Approx.

<em><u>The minimum power output of the compressor is 11.65kW</u></em>

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4 years ago
Ai r is compressed by a 30-kW compressor from P1 to P2. The air t emperature i s maintained constant at 25oC during thi s proces
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Answer:

The rate of entropy change of the air is -0.10067kW/K

Explanation:

We'll assume the following

1. It is a steady-flow process;

2. The changes in the kinetic energy and the potential energy are negligible;

3. Lastly, the air is an ideal gas

Energy balance will be required to calculate heat loss;

mh1 + W = mh2 + Q where W = Q.

Also note that the rate of entropy change of the air is calculated by calculating the rate of heat transfer and temperature of the air, as follows;

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