Answer:
Molecular formula = N2O4
Explanation:
The empirical formula of a compound is NO2. Its molecular mass is 92g/mol. What is its molecular formula?
Step 1: Data given
The empirical formula = NO2
The molecular formula = NO2
Molar mass N = 14 g/mol
Molar mass O = 16 g/mol
Step 2: Calculate molecular mass of the empirical formula
Molar mass NO2 = molar mass N + Molar mass of 2*O
Molar mass NO2 = 14 + 2*16
Molar mass = 46 g/mol
Step 3: Calculate the molecular formula
We have to multiply the empirical formula by n
n = molecular mass / molecular mass of the empirical formula
n = 92 g/mol / 46 g/mol
n = 2
We have to multiply the empirical formula by 2
Molecular formula = 2*(NO2)
Molecular formula = N2O4
Answer:
In thioformaldehyde molecule,
Central atom - C
lone pairs on central atom - zero
Ideal bond angle between the carbon -hydrogen bonds - 
Compared to the ideal angle, you would expect the actual angle between the carbon-hydrogen bonds to be
.
Explanation:
The structure of thioformaldehyde is as follows. (in attachment).
From the structure,
Central atom - C
There is no lone pairs are present on the carbon atom, Hence,lone pairs on central atom - zero
The geometry of thioformaldehyde is Trigonal planar.
Hence, the ideal bond angle is
.
Ideal bond angle between the carbon -hydrogen bonds - 
All bonds in the thioformaldehyde is similar. Therefore,actual angle between the carbon-hydrogen to be
.
Calm weather would be the answer
Answer:
Multiply the number of moles in the product by the molecular weight of the product to determine the theoretical yield.
Explanation:
For example:
If you created 0.5 moles of Aluminium Oxide the molecular weight of Aluminium Oxide is 101.96g/mole, so you would get 50.98g as the theoretical yield.
So multiply,..
101.96x0.5= 50.98
This is the correct way to calculate the theoretical yield
......
Type of NR: alpha 235 U —> + 231 Th 92 ___ 90
Answer: ²³⁵92U → ⁴2He(2p,2n) + ²³¹90Th.
Answer: ²³⁵92U → Helium nucleus + ²³¹90Th.
Explanation : This is typical Alpha decay, as an alpha is a Helium Nucleus. The Alpha decay of Uranium-235 changes both the mass number and the atomic number of the element from 235 to 231 and from 92 to 90. The mass number decreases by 4, and the atomic number decreases by 2. This gives rise to the formation of a new element - Thorium-231.
Hope this helps!