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galben [10]
3 years ago
9

What is the difference between being imaginative in doing science and doing psuedoscience?

Chemistry
1 answer:
Dovator [93]3 years ago
4 0
Being imaginative in doing science is using your knowledge and creativity to make innovative ideas, while psuedoscience is using sources that are not true and do not use actual science. Example being ads that say "Wow you will not believe what how this oil cured cancer!".
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Interpreting the periodic table
Goryan [66]

Here is an image of the periodic table. Hope this helps.

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3 years ago
Original Source Material
Alla [95]

Answer:

This is not plagiarism      

Explanation:

Plagiarism maybe defined as the practice or process of copying or imitating another person's concept or idea or writing and pretending that these are their own work.  It involves violating the copyright laws.

In the given context, the given student version of paragraph is not plagiarism as words are different from the original writing. And the bibliography reference as well as the citation are correct.

Hence the student version of writing is not a plagiarism.

5 0
3 years ago
(?)Li2O + (?)H2O → (?)LiOH
pav-90 [236]

Answer:

Li2O+H2O---->(2)LiOH

Explanation:

you have to balance the equation and not all the blanks have to be filled all the time but if it makes it easier for you in the first 2 question marks you can put a 1 which isnt necessary but if ur a visual person it will help.

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6 0
3 years ago
Need structural formula for each 12, HOCH a CH 1 Dipherylamine.
guajiro [1.7K]
12) Ethylene glycol and <span>Diphenylamine
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<span>attached images
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5 0
3 years ago
What is the product of the unbalanced combustion reaction below?<br> C4H10(g) + O2(g) →
Afina-wow [57]

Answer:

Option C . CO2(g) + H2O(g)

Explanation:

When hydrocarbon undergoes combustion, carbon dioxide (CO2) and water (H2O) are produced.

C2H4(g) + O2(g) —› CO2(g) + H2O(g)

Thus, the product of the unbalanced combustion reaction is:

CO2(g) + H2O(g)

Thus, we can balance the equation as follow:

C2H4(g) + O2(g) —› CO2(g) + H2O(g)

There are 2 atoms of C on the left side and 1 atom on the right side. It can be balanced by putting 2 in front of CO2 as shown below:

C2H4(g) + O2(g) —› 2CO2(g) + H2O(g)

There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balanced by putting 2 in front of H2O as shown below:

C2H4(g) + O2(g) —› 2CO2(g) + 2H2O(g)

There are a total of 6 atoms of O on the right side and 2 atom on the left side. It can be balanced by putting 3 in front of O2 as shown below:

C2H4(g) + 3O2(g) —› 2CO2(g) + 2H2O(g)

Thus, the equation is balanced.

5 0
3 years ago
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