Answer:
85.654988MHz
Explanation:
f = C/λ
λ (Lambda) = Wavelength in meters
c = Speed of Light (299,792,458 m/s)
f = Frequency (MHz)
299,792,458 m/s. ÷ 3.5. = 85.654988MHz
Answer:
As the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
Explanation:
As the object is moving towards the lens then in that case first the image will form between the focus and double the distance of focus.
So here the image is diminished
now when the object is at large distance from from lens then its image will form at focus and it is of very small size
Now as the object comes closer to the lens till the object distance is 2F the image size will increase but smaller then object size
Now when object is between F and 2F then the image size will be more than object size and it will increase to infinite magnification
So overall we can say that as the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
Answer:
V4=9.197v
Explanation:
Given:
V1= 18v ,V2= 12v ,r1=r5=58ohms ,r2=r6=124ohms , r3=47ohms ,r4= 125ohms
V4= I4R4 = V2/(R4 + R5)×R4
V4= 12×125 /(125 + 58)
V4=1500/183 =9.197v
