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3 years ago

How much energy is needed to melt 5 g of ice? The specific latent heat of melting for water is 334000 J/kg.

Physics

1 answer:

Katen [24]3 years ago

5 0

Answer:

The needed energy to melt of ice is 1670 J.

Explanation:

Given that,

Mass of ice = 5 g

Specific latent heat = 334000 J/kg

We need to calculate the energy

Using formula of energy

$Q=mL$

Where, m = mass

L = latent heat

Put the value into the formula

$Q=5\times10^{-3}\times334000$

$Q=1670\ J$

Hence, The needed energy to melt of ice is 1670 J.

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A bus travels from el Paso, texas, to chihuahua, mexico, in 5 hr with an average velocity if 75km/hr to the south. How far is Ch

katen-ka-za [31]

375km

Explanation:

Given parameters:

Time of travel = 5hr

Average velocity = 75km/hr south

Unknown:

Displacement between Chihuahua and El paso = ?

Solution:

Velocity is the rate of change of displacement of a body with time. It is a vector quantity that has both magnitude and direction;

Velocity = $\frac{displacement}{time}$

Since the unknown is displacement;

displacement = velocity x time

input the values;

displacement = 75km/hr x 5hr = 375km

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3 years ago

High-level clouds usually occur above 20,000 ft. Which is the best description of the clouds’ appearance?

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D. Thin and composed of Ice crystals

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4 years ago

The SAME amount of current I passes through three different resistors. R2 has twice the cross-sectional area and the same length

Snezhnost [94]

Answer:

resistor R₂ has the lowest current density

Explanation:

The current density is

j = I / A

now let's analyze each case

a) R₂ has an area 2A₀ and a length L₀ that R₁

b) R₃ has an area Ao and a length 3L₀ what R₁

we can see that all the area is given in relation to the resistance R₁

the current density in R₁ is

j₁ = I / A₀

the current density in R₂

j₂ = I / 2A₀

j₂ 2 = ½ I/A₀

the current density in R₃

j₃ = I / A₀

j₂ < j₁ = j₃

therefore resistor R₂ has the lowest current density

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3 years ago

A convex mirror has a focal length of 15cm. If the object is 35cm from the mirror and is 2cm tall, what is the magnification? Ro

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Answer:

The magnification is 0.3

Explanation:

Given:

The focal length of the convex mirror, f = 15 cm

for convex mirror f = -f = -15 cm

The distance of object, u = 35 cm

Height of the object, h = 2 cm

Now, using the mirror formula, we have

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

where, v is the distance of the image

on substituting the values, we get

$\frac{1}{-15}=\frac{1}{35}+\frac{1}{v}$

$-\frac{1}{v}=\frac{1}{35}-\frac{1}{-15}$

v = -10.5 cm

now, the magnification (m) is given as:

m = $-\frac{v}{u}$

on substituting the values, we get

m = $-\frac{-10.5}{35}$

m = 0.3

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3 years ago

a scientist heats a piece of iron until it is glowing white–hot. he places the metal inside a metal box. he removes all of the a

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3 years ago

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