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2 years ago

Which describes how the same force affects a small mass and a large mass

1 answer:

5 0

You shall use the equation for force given by the second Law of Newton, this is F = m*a, where F is the net force that acts over the object, m is the mass of the object and a is the acceleration that the object will acquire. From that equation you can find a = F/m, which means that a is direct proportional to F and invsersely related to m. So, small masses accelerate faster than large masses, and <span>the answer is the option B. the small mass accelerates faster.</span>

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Anna11 [10]

Answer:

In a biology experiment the number of yeast cells is determined after 24 hours of culture at different temperatures. a) Identify the independent and dependent variables in the experiment. b) Draw the graph of the

Explanation:

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2 years ago

The sun is 150,000,000 km from the earth.

aniked [119]

Answer:

<h3>What is the angular speed of the earth around the sun? </h3>

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$7.2921159 × 10 {}^{ - 5} \: \: \frac{radians}{second}$

<h3>What is the tangential speed of the earth? </h3>

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2 years ago

Iron filings scattered around a magnet will be most strongly drawn toward the _____.

victus00 [196]

<span>The answer is towards <span>the poles. This is because, at the poles of the magnet, the magnetic field lines get closer together hence indicating that the magnetic force is stronger here. The fields are closest together at the center of the magnet and farthest at the outside side of the magnet. </span></span>

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2 years ago

Read 2 more answers

Someone help me please.

Soloha48 [4]

1/2*2.8*x^{2}=2.8*9.81*1.50

X=5.425

Because K.E=1/2*M*V² and it is equal to P.E in the conservation of energy which means its K.E=P.E

P.E=m*g*h

So K.E equals 1/2*2.8*(5.425)²=41.20

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2 years ago

An object on a spring whose constant is 30. N/m

MrRa [10]

The mass of the object is 0.0076 kg

Explanation:

The frequency of a mass-spring system (simple harmonic motion) is given by

$f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}$

where

f is the frequency

k is the spring constant

m is the mass

For the mass-spring system in this problem, we know:

k = 30 N/m is the spring constant

f = 10 Hz is the frequency

Solving the equation for m, we find the mass:

$m=\frac{k}{(2\pi f)^2}=\frac{30}{(2\pi (10))^2}=0.0076 kg$

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2 years ago