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2 years ago

A scholar climbs up 8 m of stairs while using 500 J of work in 10 seconds. What is their power?

Physics

1 answer:

ehidna [41]2 years ago

7 0

Answer:

according to the new geometry lesson alcometry which will after 11 years in geometry

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the strength s of a rectangular wooden beam is proportional to its width and the cube of is septh. If the beam is to be cut from

babymother [125]

Answer:

Can see it in the pic

Explanation:

Can see it in the pic

4 0

3 years ago

A hiker begins a trip by first walking 25.0 km southeast from her car. She stops and sets up her tent for the night. On the seco

Sunny_sXe [5.5K]

Answer:

(a)

$x_1=17.68km\\y_1=-17.68km\\x_2=20km\\y_2=34.64km$

(b) $r=41.32km$

$\alpha =24.23^o$

Explanation:

Let us take the north direction to be the positive y-axis and the east to be positive x-axis.

First day:

25.0 km southeast, which implies $45^o$ south of east. The y-component will be negative and the x-component will be positive.

$x_1=25cos45^o=17.68km$

$y_1=-25sin45^o=-17.68km$

Second day:

She starts off at the stopping point of last day. This time, both the y- and x-components are positive.

$x_2=40cos60^o=20km$

$y_2=40sin60^o=34.64km$

Therefore, total displacements:

$x=x_1+x_2=(17.68+20)km=37.68km$

$y=y_1+y_2=(-17.68+34.64)km=16.96km$

Magnitude of displacements,

$r=\sqrt{x^2+y^2}=41.32km$

Direction,

$\alpha =tan^{-1}(\frac{y}{x})=24.23^o$

6 0

3 years ago

Consider a cloudless day on which the sun shines down across the United States. If 2073 kJ of energy reaches a square meter ( m

Mnenie [13.5K]

The total amount of energy per hour is $2.039\cdot 10^{16} kJ$

Explanation:

In this problem we are told that the amount of energy reaching a square meter in the United States per hour is

$E_1 = 2073 kJ$

The total surface area of the United States is

$A=9.834\cdot 10^6 km^2$

And converting into squared metres,

$A=9.834\cdot 10^6 \cdot 10^6 = 9.834\cdot 10^{12} m^2$

Therefore, the total energy reaching the entire United States per hour is given by:

$E=AE_1 = (9.834\cdot 10^{12})(2073)=2.039\cdot 10^{16} kJ$

Learn more about energy and power:

brainly.com/question/7956557

#LearnwithBrainly

5 0

3 years ago

The mass of a star is 1.210×1031 kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter su

balandron [24]

The new period will be 2.486 days.

<h3>What is the period?</h3>

The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.

Given data;

Mass of a star,m= 1.210×10³¹ kg

The time period for one rotation of the star, T = 20.30 days

D' = 0.350 D

R' = 0.350 R

From the law of conservation of angular momentum;

$\rm I \omega = I' \omega' \\\\ \frac{2}{5} MR^2 \times \frac{2 \pi }{T}=\frac{2}{5} MR'^2 \\\\ R^2 \times \frac{1}{T}= R'^2 \times \frac{1}{T} \\\\ T' = \frac{R'^2T}{R^2} \\\\ T' = \frac{(0.350 R)^2 \times 26.1 }{R^2} \\\\T' = 0.1225 \times 20.30 \\\\ T'= 2.486 \ days$

Hence, the new period will be 2.486 days.

To learn more about the period, refer to the link;

brainly.com/question/569003

#SPJ1

8 0

1 year ago

If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, what be

Vlad1618 [11]

<span>Usually, If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, the statement which would best describe what would occur is the last one : </span><span>The water and the metal's temperatures will reach the same temperature. I choose this one because this is a nice example of how the nature tries to reach the balance. Hope it helps! Regards.</span>

7 0

3 years ago