Answer:
D. Top is emission; bottom absorption.
Explanation:
Emission and spectrum of elements are due to the element absorbing or emitting wavelength of e-m energy. Elementary particles of elements can absorb energy from a ground state to enter an excited state, creating an absorption spectrum, or they can lose energy and fall back to a lower energy state, creating an emission spectrum. A simple rule to differentiate between an emission and an absorption spectrum is that: "all absorbed wavelength is emitted, but not all emitted wavelength is absorbed."
From the image, the lines indicates wavelengths. We can see that all of the wavelengths of the bottom absorption spectrum coincides with some of the wavelength of the upper emission wavelengths.
Answer:
a
The direction of the wave propagation is the negative z -axis
b
The amplitude of electric and magnetic field are 
,
respectively
Explanation:
According to right hand rule, your finger (direction of electric field) would be pointing in the positive x-axis i.e towards your right let your palms be face toward the direction of the magnetic field i.e negative y-axis (toward the ground ) Then anywhere your thumb stretched out is facing is the direction of propagation of the wave here in this case is the negative z -axis
The Intensity of the wave is mathematically represented as
Given that 
Making 
the subject we have
Substituting values as given on the question
![E_{rms} = \sqrt{\frac{7.43 *10^7[\frac{W}{m^2} ]}{0.5 * 3.08*10^8 *8.85*10^{-12}} }](https://tex.z-dn.net/?f=E_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B7.43%20%2A10%5E7%5B%5Cfrac%7BW%7D%7Bm%5E2%7D%20%5D%7D%7B0.5%20%2A%203.08%2A10%5E8%20%2A8.85%2A10%5E%7B-12%7D%7D%20%7D)
The amplitude of the electric field is mathematically represented as
The amplitude of the magnetic field is mathematically represented as
Substituting value
Answer:
Explanation:
Answer:
Explanation:
Given that,
System of two particle
Ball A has mass
Ma = m
Ball A is moving to the right (positive x axis) with velocity of
Va = 2v •i
Ball B has a mass
Mb = 3m
Ball B is moving to left (negative x axis) with a velocity of
Vb = -v •i
Velocity of centre of mass Vcm?
Velocity of centre of mass can be calculated using
Vcm = 1/M ΣMi•Vi
Where M is sum of mass
M = M1 + M2 + M3 +...
Therefore,
Vcm=[1/(Ma + Mb)] × (Ma•Va +Mb•Vb
Rearranging for better understanding
Vcm = (Ma•Va + Mb•Vb) / ( Ma + Mb)
Vcm = (m•2v + 3m•-v) / (m + 3m)
Vcm = (2mv — 3mv) / 4m
Vcm = —mv / 4m
Vcm = —v / 4
Vcm = —¼V •i
London is making in their room by the way I’m just using this as
Free pouts
Answer:
2nd bscause there is a reaction
