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Brilliant_brown [7]
3 years ago
6

PLEASE HELP!!! I have so much work left to do. PLEASE!!!

Physics
1 answer:
Neko [114]3 years ago
6 0

Answer:

the answer is C.

Explanation:

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Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th
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Answer:

Explanation:

a )  V = 3 cos(0.5t)

differentiating with respect to t

dv /dt = -3 x .5 sin0.5t

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acceleration = - 1.5 sin 0.5t

when t = 3 s

acceleration = - 1.5 sin 1.5

= - 1.496 ms⁻²

v = 3 cos.5t

b )  dx/dt = 3 cos 0.5 t

dx = 3 cos 0.5 t dt

integrating on both sides

x = 3 sin .5t / .5

x = 6 sin0.5t

At t = 2 s

x = 6 sin 1

x = 5.05 m

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3 years ago
a vertical polarizing filter is used on the lens of a camera. Which of the following do not strike the lens?
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A vertical polarizing filter is used on the lens of a camera,  they block out the light that is horizontally polarized, so they allow all of the vertically polarized<span> light to pass through.</span>
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3 years ago
A party shop delivers helium-filled balloons to homes and businesses. The owners realize from experience that on hot summer days
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Where is the sun in the life cycle? HELP ITS A FINAL EXAM
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3 years ago
The Coulomb force between two charges q1 and q2 at separation r in the air is 10N. If half of the separation is filled with medi
adoni [48]

Answer:

The value of new coulomb force is 1.43 N.

Explanation:

Given;

Coulomb's force in vacuum (air), F_v = 10 N

dielectric constant, K = 7

The Coulomb's force between two charges separated by a distance r in a vacuum is given as;

F_v = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2}

The Coulomb's force between two charges separated by a distance r in a medium with dielectric constant is given as

F_m = \frac{1}{4\pi K\epsilon_0} \frac{q_1q_2}{r^2}

Take the ratio of the two forces;

\frac{F_v}{F_m} = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2} \ \times \ \frac{4\pi K\epsilon_0 r^2}{q_1q_2} = K\\\\\frac{F_v}{F_m} = K\\\\\frac{10}{F_m} = 7\\\\F_m = \frac{10}{7} \\\\F_m = 1.43 \ N

Therefore, the value of new coulomb force is 1.43 N.

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